It's definitely A, gotta be.
First you would simplify the equation <span>(7x²+2x+5)+(3x²-8x-10) lets start with the first part
</span><span>(7x²+2x+5)
</span>7x² + 2x which = 49x + 2x which also = 51x Then you add the last part (+5)
51x + 5
Now you simplify the last part.
<span>(3x²-8x-10)
</span>3x²-8x which=9x - 8x which also = 1x or simply x Then add the last part (-10) Which you'll get x-10
51x + 5) + (x - 10) = 52x -5
so your answer is 52x - 5
Speed=distance/time
suppose the distance of the first day is d, and the time is t
distance of the second day: d+0.17d=1.17d
time of the second day: t+0.2t=1.2t
speed of the second day: 1.17d/1.2t=0.975(d/t)=(1-0.025)(d/t)
so the speed of the second day is 2.5% slower than the first day.
3/4 ( (-50+2)/5)
= 3/4 ( -48/5)
= 3/4 * -48/5
= -36/5
Answer:
4 weekdays and 2 weekends.
Step-by-step explanation:
6 days.
x = weekdays
y = weekends
7x = amount with weekdays
12y = amount with weekends
7x + 12y = 52, total
x + y = 6, amount of days
solve double variable equation
x = 6 - y, plug in to 1st equation
7(6 - y) + 12y = 52
42 - 7y + 12y = 52
5y = 10
y = 2 weekends
2 + x = 6
x = 4 weekdays
