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kap26 [50]
3 years ago
8

How do I solve this using f.o.i.l (Factoring trinomials)

Mathematics
1 answer:
kodGreya [7K]3 years ago
6 0
It’s not factorable, that’s it’s final form
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2. Janice and Jasmine were each given a piece of ribbon of equal length. Janice cuts her ribbons into equal lengths of 2 m, whil
Anna35 [415]

Answer:

10m.

Step-by-step explanation:

Since there is no remainder we simply need to find the least common multiple of each of the lengths of Janice and Jasmin's strings until we find a multiple that matches for each. Like so...

2*1 = 2                    5*1 = 5

2*2 = 4                   5*2 = 10

2*3 = 6

2*4 = 8

2*5 = 10

Finally, we have found the first common multiple which is 10m. That means that the shortest equal length for both Janice's and Jasmin's ribbon is 10m.

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