Given:
The equation of a circle is:

To find:
The center and radius of the circle.
Solution:
We have,

To make complete square add square of half of x and square of half of y on both sides.




...(i)
The standard form of a circle is:
...(ii)
On comparing both sides, we get

Therefore, the center of the circle is (-2,3) and the radius is 3 units.
Answer:
272
Step-by-step explanation:
calculator
Answer:
We see that the big triangle is an equilateral triangle, so all its angles will measure 60°. Therefore x° will be 60° - 30° = 30°, as he's the base angle of an isosceles triangle having the other base angle of 30°. y will simply be 180° - 60° (remembering that the sum of the angles in a triangle is always 180°).
That "ad^3" bothers me; I'm not sure what you mean here.
I'm going to assume that you have (1/4*a*d^3)^2.
If that's the case, then you have (1/4)^2 * a^2 * d^6 = (1/16)*a^2*d^6.
If this is not what you were hoping for, double check to ensure that you have copied down this problem exactly as it was presented.
3x + y = 10
x - 4y = -1
Multiply the 2nd equation by -3
-3x +12y = 3
Add the 1st equation to the 3rd equation:
13y = 13
Divide both sides by 13:
y = 1
Answer: A) 1