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NeTakaya
3 years ago
11

Surface Area of a Cylinder=2πr2+2πrh.

Mathematics
2 answers:
lawyer [7]3 years ago
4 0
The answer is 256pi if you have a calculator, and it says to put it in 3.14 for pi, do the same steps I show here, but instead of pi, you would put 3.14. But I hope this helps you

Elodia [21]3 years ago
3 0
2pi(4)^2= 100.5
2pi(4)(28)= 703.7
703.7+100.5= 804.2
The answer is 804.2cm^2
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Answer:

V = 64 cm^3

Step-by-step explanation:

Volume is length times width times height

V = l*w*h

V = 4*4*4

V = 64 cm^3

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Please explain who would i be able to get the answer to this problem.
SashulF [63]

We have been an quadratic equation 8k-k^{2} =42 and we are asked to solve our equation.

Upon subtracting 42 from both sides of our equation we will get,

8k-k^{2}-42 =0

-k^{2}+8k-42 =0

k^{2}-8k+42 =0

Let us check whether our quadratic equation has any real roots using discriminant formula.

D=b^{2}-4ac  

Upon substituting our given values in discriminant formula we will get,

D=(-8)^{2} -4(1\cdot 42)

D=64 -168

D=-104

We can see that D is less than zero, so our quadratic equation has no real roots.

Now we will use imaginary number i to find complex roots of our quadratic equation.

We will use -1 =i^{2} to solve our equation.

k=\frac{-b \pm \sqrt{b^{2}-4ac} } {2a}

k=\frac{--8 \pm \sqrt{(-8)^{2}-4(1*42)} } {2*1}

k=\frac{8 \pm \sqrt{64-168 }} {2}

k=\frac{8 \pm \sqrt{-1\cdot 104} } {2}

k=\frac{8 \pm \sqrt{i^{2}\cdot 104} } {2}

k=\frac{8\pm 2i \sqrt{26}}{2}

k=4\pm i \sqrt{26}

Therefore, our answer will be k=4\pm i \sqrt{26}.


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3 years ago
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Natasha2012 [34]

Answer:

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1/4 = 2/8       2/8-1/8=1/8

7 0
4 years ago
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