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Yuri [45]
2 years ago
5

In AKLM, m = 86 inches, k = 56 inches and ZL=85°. Find ZM, to the nearest degree.

Mathematics
1 answer:
lara31 [8.8K]2 years ago
8 0
Please show a pic so i can understand better
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Form the intersection for the following sets. E = {1, 2, 3} F = {101, 102, 103, 104} E ∩ F =
madam [21]
The intersection of two sets is a set that contains elements that are common to both sets.
There are no common elements in sets E and F, so the answer is the empty set.

<span>E ∩ F =  { }</span>
3 0
3 years ago
Solve the equation 3b1b-8=4​
joja [24]

Answer:

b = 2

Step-by-step explanation:

3b1b-8 = 4

       +8  +8

3b1b = 12

3b^2 = 12

/3          /3

b^2 = 4

\sqrt{b^2}   \sqrt{4}

b = 2

6 0
3 years ago
Reflect the shape over the line shown !
snow_lady [41]
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2 years ago
What is the rule for the sequence with the first four terms below? 0.5, 0.25, 0, –0.25
elena55 [62]

Answer:

subtract .25 each time x-.25

Step-by-step explanation:

6 0
3 years ago
What is the image point of (-12, -8) after the transformation R270° 0 D. ?
Gennadij [26K]

Given:

The point is (-12,-8).

Rule of transformation is R_{270^\circ}\circ D_{\dfrac{1}{4}}.

To find:

The coordinates of image after transformation.

Solution:

According to the rule of transformation R_{270^\circ}\circ D_{\dfrac{1}{4}}, first the point is dilated by factor \dfrac{1}{4} with origin as center of dilation after that it was rotated 270 degrees anticlockwise.

If a point is dilated by factor \dfrac{1}{4} with origin as center of dilation, then

(x,y)\to \left(\dfrac{1}{4}x,\dfrac{1}{4}y\right)

(-12,-8)\to \left(\dfrac{1}{4}(-12),\dfrac{1}{4}(-8)\right)

(-12,-8)\to \left(-3,-2\right)

If a point is rotated 270 degrees anticlockwise, then

(x,y)\to (y,-x)

(-3,-2)\to ((-2),-(-3))

(-3,-2)\to (-2,3)

Therefore, the coordinates of image after transformation are (-2,3).

3 0
3 years ago
Read 2 more answers
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