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jekas [21]
3 years ago
11

An Ice Cream Factory makes 3:1 tubs of ice cream to boxes of ice cream bars. If the factory makes 165 tubs of ice cream in a day

, how many boxes of ice cream bars were made?​
Mathematics
1 answer:
Ad libitum [116K]3 years ago
7 0

Answer:

55 boxes of ice cream

Step-by-step explanation:

Tubs of ice cream : boxes of ice cream = 3 : 1

If the factory makes 165 tubs of ice cream in a day, how many boxes of ice cream bars were made?

Boxes of ice cream made in a day = x

Tubs of ice cream : boxes of ice cream = 165 : x

Equate both ratios to find x

3 : 1 = 165 : x

3/1 = 165/x

Cross product

3 * x = 1 * 165

3x = 165

x = 165/3

x = 55

Boxes of ice cream made in a day = 55

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3 years ago
4. Two friends, Sequoia and Raven, sold organic chap sticks at the local market.
Nina [5.8K]

Answer:

Sequoia sold 2 chap sticks while Raven sold 4.

Step-by-step explanation:

Since two friends, Sequoia and Raven, sold organic chap sticks at the local market, and Sequoia sold her chap sticks for $ 4 and Raven sold hers for $ 3 each, and in the first hour, their total combined sales were $ 20, if in the first hour, the friends sold a total of 6 chap sticks between them, to determine the number of chap sticks each of the friends sold during this time the following calculation must be performed:

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7 0
3 years ago
Plz hurry!!!! thank you!!!!
Nikitich [7]

Answer:

Area of trapezium = 4.4132 R²

Step-by-step explanation:

Given, MNPK is a trapezoid

MN = PK and ∠NMK = 65°

OT = R.

⇒ ∠PKM = 65° and also ∠MNP = ∠KPN = x (say).

Now, sum of interior angles in a quadrilateral of 4 sides = 360°.

⇒ x + x + 65° + 65° = 360°

⇒ x = 115°.

Here, NS is a tangent to the circle and ∠NSO = 90°

consider triangle NOS;

line joining O and N bisects the angle ∠MNP

⇒ ∠ONS = \frac{115}{2} = 57.5°

Now, tan(57.5°) = \frac{OS}{SN}

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Now, draw a line parallel to ST from N to line MK

let the intersection point be Q.

⇒ NQ = 2R

Consider triangle NQM,

tan(∠NMQ) = \frac{NQ}{QM}

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⇒ QM = \frac{2R}{2.1445}

QM = 0.9326 R .

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Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).

⇒ A = (\frac{NP + MK}{2}) × (ST)

       = (\frac{1.274 R + 3.1392 R}{2}) × 2 R

       = 4.4132 R²

⇒ Area of trapezium = 4.4132 R²

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3 years ago
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