Find the median of each set:-
Median is middle number of a data set. If a data set has an odd number of numbers then the median is the middle number when ordered form least to greatest but if its an even number you have to find the mean for the middle 2 numbers when ordered for least to greatest.
A.
1.2, 2.4, 3.2, 3.2, 3.6, 4.0, 4.1, 4.7
Even numbers = 8
3.2 + 3.6 = 6.8
6.8 ÷ 2 =
Median = 3.4
So this shows that A isn't the answer because the median of A is 3.4, not 3.2.
B.
1.6, 2.8, 2.9, 3.1, 3.3, 3.6, 4.2, 4.5
Even numbers = 8
3.1 + 3.3 = 6.4
6.4 ÷ 2 = 3.2
Median = 3.2
<span>So this shows that B is the answer because the median of B is 3.2.
C.
1.8, 2.0, 2.0, 2.2, 3.2, 4.7, 4.8, 4.9
</span>
Even numbers = 8
2.2 + 3.2 = 5.4
5.4 ÷ 2 = 2.7
Median = 2.7
<span>So this shows that C isn't the answer because the median of C is 2.7, not 3.2.
</span>
D.
1.4, 1.7, 2.9, 3.0, 3.1, 3.2, 3.2, 3.2, 4
Odd numbers = 9
Median = 3.1
<span>So this shows that D isn't the answer because the median of D is 3.1, not 3.2.
</span>
The stem and leaf plot which median is 3.2 is B.
Answer: p - 0.2p
Step-by-step explanation:
Given the following :
Original Price of tennis racket = p
Mark down or discount on original price = 20% of original price = (20/100) × p = 0.2p
Amount after discount = Amount paid by Natasha
Amount after discount = Original price - Discount
Amount after discount = p - 0.2p
Amount paid by Natasha = p - 0.2p
the distance between 16 and -25 is 41
Answer:
Step-by-step explanation:
Solve the inequality 5x − 4y > 20 for y, as follows: Subtract 5x from both sides, obtaining:
-4y > 20 - 5x;
Then divide all terms by -4:
y < -5 +(5/4)x, where the direction of the inequality sign has been reversed because of division by a negative quantity.
Temporarily replace the < symbol with = obtaining y = -5 +(5/4)x. Now choose at least three x values and find the corresponding y values. For example:
x y = -5 +(5/4)x
0 -5
4 0
-8 -15
Now plot these three points (0, -5), (4, 0) and (-8, -15). Draw a dashed line through them. Because of the < symbol in y < -5 +(5/4)x, shade the area underneath the dashed line.
