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2 years ago

The radius of a circle is 16 feet. What is the circle's area? Use 3.14 for . square feet

Mathematics

1 answer:

Alla [95]2 years ago

7 0

Answer:

803.84 feet squared

Step-by-step explanation:

A=pi*r^2

16^2=256

256*pi=803.84

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In a right triangle, the length of one leg is 6 units. The length of the other leg is 8 units. What is the length of the hypoten

lozanna [386]

$hypotenuse = \sqrt{6^2+8^2}= \sqrt{36+64}= \sqrt{100}=10 \ units$

7 0

3 years ago

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Does anyone know how to solve this?

erik [133]

Answer:

A point in polar coordinates is written as (R, θ)

If we want to transform this point to rectangular coordinates, we get:

x = R*cos(θ)

y = R*sin(θ)

Now we can remember that the sine and cosine functions have a period of 2*pi, then:

cos(θ) = cos(θ + 2*pi)

or:

cos(θ) = cos(θ + 2*pi + 2*pi)

and so on.

Then the point (R, θ) is the same as (R, θ + 2*pi) and (R, θ + k*(2*pi))

where k can be any integer number.

Then if we have a point in polar coordinates:

(-4, -5*π/3)

Then another two polar representations of this point are:

(-4, -5*π/3 + 2*π) = (-4, -5*π/3 + 6*π/3) = (-4, π/3)

Now we can not add 2*π (nor subtract) because we would have an angle outside the range [-2*π, 2*π]

For example, if we have:

(-4, π/3 + 2*π) = (-4, 7*π/3)

And we can not change the value of the radius and get the coordinates for the same point.

So another representation could be something like:

(-8/2, π/3)

Where i just wrote -4 in another way.

Now, a really important point.

When working with polar coordinates, we always use R as a positive number (here you can see that R is negative) so this is not the standard notation for the polar representation of a point.

8 0

3 years ago

Help me solve,Brainlist for first to answer

Vanyuwa [196]

Answer:

(i) the other two sides are 6 and 6 $\sqrt{2}$

(ii) the other two sides are $\frac{4}{3} and \frac{8}{3}$

Step-by-step explanation:

(i) Sine: sin(θ) = Opposite ÷ Hypotenuse

Cosine: cos(θ) = Adjacent ÷ Hypotenuse

Tangent: tan(θ) = Opposite ÷ Adjacent

Here adjacent side = 6

opposite side = d

angle = 45°

other angles are 90° and 45°

tan (45) = Opposite ÷ Adjacent

1 = d ÷ 6

∴ d = 6 × 1 = 6

so opposite side = 6

Hypotenuse ² = opposite side ² + adjacent side²

= 6² + 6²

= 36 + 36

= 72

hypotenuse = $\sqrt{72}$

= 6 $\sqrt{2}$

the other two sides are 6 and 6 $\sqrt{2}$

(ii) here adjacent side = 4√3

angle = 30°

other angles are 90° and 60°

opposite side = d

tan ( 30) = opposite ÷ adjacent

$\frac{1}{\sqrt{3}}$ = d ÷ 4√3

$\frac{1}{\sqrt{3}}$ = d × ( $\frac{\sqrt{3}}{4}$ )

3 d = 4

therefore d = $\frac{4}{3}$

therefore opposite side = $\frac{4}{3}$

Hypotenuse ² = opposite side ² + adjacent side²

=( $\frac{4}{3}$ )² +( $\frac{4}{\sqrt{3}}$ )²

= $\frac{64}{9}$

therefore hypotenuse = $\sqrt{\frac{64}{9}}$

= $\frac{8}{3}$

the other two sides are $\frac{4}{3} and \frac{8}{3}$

7 0

4 years ago

X (dy/dx) = (y-1/y+1)-y

notsponge [240]

F' $( \frac{y-1}{y+1})-y$ =
f' $( \frac{y-1}{y+1})$ -f'(y) [/tex]=
$\frac{f'(y-1)(y+1)-f'(y+1)(y-1)}{(y+1)^2} -1$ =
$\frac{(f'(y)-f'(1))(y+1)-(f'(y)+f'(1))(y-1)}{(y+1)^2} -1$ =
$\frac{(1-0)(y+1)-(1-0)(y-1)}{(y+1)^2} -1$ =
$\frac{(1)(y+1)-(1)(y-1)}{(y+1)^2} -1$ =
$\frac{(y+1)-(y-1)}{(y+1)^2} -1$ =
$\frac{y+1-y+1}{(y+1)^2} -1$ =
$\frac{2}{(y+1)^2} -1$

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3 years ago

A migrating bird flies 341 miles in 11 hours. How many miles can the bird fly in 6 hours?

Sedaia [141]

186 because you would divide 341 by 11 and you get 31 then multiply that by 6 and you get 186. Did this help?

8 0

4 years ago

Read 2 more answers