Answer:
The probability that the last card dealt is an ace is 
.
Step-by-step explanation:
Given : A deck of ordinary cards is shuffled and 13 cards are dealt.
To find : What is the probability that the last card dealt is an ace?
Solution :
There are total 52 cards.
The total arrangement of cards is 52!.
There is 4 ace cards in total.
Arrangement for containing ace as the 13th card is 
.
The probability that the last card dealt is an ace is
Therefore, the probability that the last card dealt is an ace is .
Step-by-step explanation:
distribute the -2 to (x+1) you end up with -2x-2=8 (multiplication property). Add 2 to both sides to get rid of the -2 of the left (addition property). 8+2=10. -2x=10 divide the -2 to both sides. x=-5 (division property).
<span><span><span>Let the original number be "x".
(x-10)/4 = 2
x-10 = 8
x = 18 (original number of pieces of candy.)</span></span></span>
Answer:
24%
Step-by-step explanation:
I think this is right. im sorry if its not but i went to a percent calculator and checked my answer. hope this helped :)
Perimeter=2L+2W, in this case L=80+2(25) and W=170+2(25) so
P=2(L+W)=2(80+50+170+50)
P=2(350)=700m
