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Lady bird [3.3K]
3 years ago
5

Help, pls. In an algebra test rn

Mathematics
1 answer:
Nata [24]3 years ago
6 0
I cannot see the picture
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The amount that Jimmy paid for his meals the four days, $6.45, $21.38, $1.99, $7.99, $16, $0, $7.99, $18.95, $4.30, $10.35, $18.
ella [17]

Answer:

$7.99

Step-by-step explanation:

Arrange numbers in numerical order: $0, $1.99, $4.30, $6.45, $7.99, $7.99, $10.35, $16, $18.20, $18.95, $21.38.

Count how many numbers you have, 11.

11 is an odd number so, the number in the middle of the data set is the median.

Final answer: $7.99 is the median.

7 0
2 years ago
Could someone help me finding out the missing answers?
Tema [17]

Answer:

See below.

Step-by-step explanation:

The Slope of PQ is (v - z) / (w - x).

The slope of P'Q' =

(v + b) - (z + b)

---------------------   =   (v - z) / (w - x)

(w + a - (x + a)

Both lines have a slope that is (v - z)/ (w - x).

So both lines are parallel.

7 0
3 years ago
A die is rolled. If you roll a 1, 2 or 3, you will toss 10 coins. If you roll a 4, 5 or 6, you will toss 20 coins. Let X denote
trasher [3.6K]

Answer:

a) The support of X is {0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20}

b) The mean of X is 7.5

c) The variance of X is 10

Step-by-step explanation:

a) Since you can toss up to 20 coins, and from that you can obtain any number of heads from 0 to 20, then the support of X {0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20}.

b) To compute the mean of X, we need to see how is the <em>behavior</em> of X. Since 3 dices will gives 10 coins to toss and the other 3 will give us 20, then there is a probability of 1/2 that we tossed 10 coins and a probability of 1/2 that we tossed 20.

The random variable X, conditioned to the event 'The dice is 1,2 or 3' (or equivalently, 10 coins are tossed), will have a binomial distribution with paramenters n = 10, p = 1/2. The mean of X in this case is np = 5. If X is conditioned to the event 'The dice is 4,5 or 6', then X will have also binomial distribution, but this time with paramenters n = 20, p = 1/2. The mean of X in this case is 20*1/2 = 10.

Since each event we conditioned in had probability 1/2 to occur, then E(X) = 1/2 * 5 + 1/2 * 10 = 7.5.

c) Remember that V(X) = E(X²)- E(X)². Since we alredy know the mean of X, we just need to compute the mean of X squared.

The variance of a binomial distribution Z with paramenters n and p is

V(Z) = np(1-p)

since V(Z) = E(Z²)- E(Z)² = E(Z²)- n²p², then

E(Z²) = V(Z) + E(Z)² = np(1-p) + n²p² = p²(n²-n) + np

Therefore

E(X²) = E(X² | 10 coins are tossed) * 1/2 + E(X² | 20 coins are tossed) * 1/2 =

1/2*(0.5²(10²-10) + 5) + 1/2*(0.5²(20²-20) + 10) = 13.75 + 52.5 = 66.25

As a consecuence

V(X) = 66.25 - 7.5² = 10

The variance of X is 10.

5 0
3 years ago
Order the steps and justifications in solving the system of linear equations.
bezimeni [28]

Answer:

eqaution 1: Proportinal

eqaution 2:Proportinal

Step-by-step explanation:

4 0
3 years ago
Select all of the equations for which x = 7 is a solution?
9966 [12]

Answer:

d x – 3 = 4

e 4x + 1 = 29

hope it helps

8 0
3 years ago
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