The first-serve percentage of a
tennis player in a match is normally distributed with a standard deviation of
4.3%. If a sample of 15 random matches of
the player is taken, the mean
first-serve percentage is found to be 26.4%. The margin of error of the sample
mean is 83.71%.
Answer:
The answer is:
30 minutes.
Step-by-step explanation:
We are given the following information:
at 160 m/min, tool life = 5 min.
at 120 m/min, tool life = 17 min.
This means that as the speed reduced from 160 m/min to 120 m/min, the tool life increased from 5 min. to 17 min, hence the difference between the changes are:
speed = 160 - 120 = 40 m/min
tool life = 17 - 5 = 12 min.
Therefore, it can be concluded that a change of speed of 40 m/min, increases the tool life by 12 min.
40 m/min = 12 min
∴ 1 m/min = 12/40 min.
∴ 100 m/min = 12/40 × 100 = 0.3 × 100 =30 min.
Answer:
1 side would be 4.0, then the next 4.0, the very botton is a 90 degree
Step-by-step explanation:
5 9/10 .........................................
