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3 years ago

3x^2+8x-6=0 solve with quadratic formula

Mathematics

1 answer:

vivado [14]3 years ago

7 0

Answer:

The answer is x = -4 ± √34 /3

Step-by-step explanation:

Solve the equation for x by finding a , b , and c of the quadratic then applying the quadratic formula.

Hoped this helped!

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I have 366 points. If anyone gets this correct i will give you 100 of them!

Tasya [4]

Answer:

Step-by-step explanation:

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7 0

3 years ago

Read 2 more answers

The perimeter of an equilateral triangle is 186 cm. what is the length of one side of the triangle?

AlexFokin [52]

186÷3= 62

So, the length of one side of the triangle is 62 cm

Hope this helps! :)

6 0

4 years ago

10. What is the value of x in this equation?

taurus [48]

Answer:

$- 8\frac{ 1}{ 2}$

Step-by-step explanation:

$- 4x + 8 = 42 \\ - 4x = 42 - 8 \\ - 4x = 34 \\ x = \frac{ 34}{ - 4} \\ x = - \frac{ 17}{ 2} \\ x = - 8\frac{ 1}{ 2} \: or \: x = - 8.5$

3 0

3 years ago

Question is on the picture

aleksklad [387]

Answer:

12/5

Step-by-step explanation:

tan A = opp/adj

For angle theta, 12 is the opposite leg.

13 is the hypotenuse.

We were not given the length of the adjacent leg, but we can use the Pythagorean theorem to find it.

a^2 + b^2 = c^2

a^2 + 12^2 = 13^2

a^2 + 144 = 169

a^2 = 25

a = 25

The adjacent leg has a length of 5.

tan theta = opp/adj

tan theta = 12/5

Answer: 12/5

4 0

3 years ago

Which expression is equivalent to (4+3i)^2+(6-I)^2

zhenek [66]

Answer:

$\large\boxed{(4+3i)^2+(6-i)^2=42+12i}$

Step-by-step explanation:

$(4+3i)^2+(6-i)^2\qquad\text{use}\ (a\pm b)^2=a^2\pm2ab+b^2\\\\=4^2+2(4)(3i)+(3i)^2+6^2-2(6)(i)+i^2\\\\=16+24i+9i^2+36-12i+i^2\qquad i=\sqrt{-1}\to i^2=-1\\\\=16+24i+9(-1)+36-12i+(-1)\\\\=16+24i-9+36-12i-1\qquad\text{combine like terms}\\\\=(16-9+36-1)+(24i-12i)\\\\=42+12i$

8 0

4 years ago