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sergey [27]
3 years ago
12

Read the information in the box below.

Mathematics
2 answers:
timofeeve [1]3 years ago
8 0

Answer:

46

Step-by-step explanation:

maks197457 [2]3 years ago
3 0

Answer:

4 inches

Step-by-step explanation:

Given that :

Amount of Rainfall in October = 14 inches

Amount of Rainfall in October = 3 1/2 times more than Rainfall during September

How much rain fell.during September :

The problem is a division problem ;

Since the amount of Rainfall in October is greater, then obtaining the amount of Rainfall in September requires dividing The amount of Rainfall in October by the number of times it is more than the September rainfall;

If multiplication is applied, then tbe value obtained will be greater than 14 inches. Which makes no sense since, the Rainfall in October is much greater than that in September.

14 inches ÷ 3 1/2

14 ÷ 7/2

14 * 2 / 7

= 28 / 7

= 4 inches

Hence, the amount of Rainfall in September is 4 inches

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A small town has two local high schools. High School A currently has 750 students and is projected to grow by 45 students each y
PtichkaEL [24]

Answer: A=750 +75*t

B=900 +25*t

There would be 975 students in each high school in year 3 when they are expected to have the same number of students.

Step-by-step explanation:

A = B

750 +75*t=900 + 25*t

Solving:

75*t -25*t= 900 - 750

50*t= 150

t=3

This indicates that in year 3 both High Schools are projected to have the same number of students. To get that amount, you simply replace this value in the expressions:

A=750 +75*t= 750 +75*3= 975

B=900 + 25*t=900 + 25*3= 975

There would be 975 students in each high school in year 3 when they are expected to have the same number of students.

 

8 0
3 years ago
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Does anyone know the answer ? :(
weeeeeb [17]

Answer:

If it a khan you can go take a hint and try to find it

5 0
3 years ago
How to derive: f(w)=ln(cos(w-1))
postnew [5]
The word you're looking for is "differentiate", not "derive".

\dfrac{\mathrm d}{\mathrm dw}\ln(\cos(w-1))=\dfrac{\frac{\mathrm d}{\mathrm dw}\cos(w-1)}{\cos(w-1)}=\dfrac{-\sin(w-1)\frac{\mathrm d}{\mathrm dw}(w-1)}{\cos(w-1)}=-\dfrac{\sin(w-1)}{\cos(w-1)}=-\tan(w-1)
3 0
4 years ago
PLEASE HELP IREADY ASAAPPPPP
a_sh-v [17]

Answer:

The third one. The square in the top left can only fold to the right or down.... which means there is guaranteed to be an open side remaining on the square.

3 0
3 years ago
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Evaluate 6j 23 kl−3, when j=3, k=7, and l=33.
Katyanochek1 [597]
To evaluate the expression given above, we just have to substitute the values assigned to each variable in the expression. The expression would be:

<span>6j23kl−3

We evaluate as follows:

</span><span>6j 23 kl−3
6(3)(23)(7)(33) - 3
95631

Hope this answers the question. Have a nice day.
</span>
3 0
4 years ago
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