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nirvana33 [79]
3 years ago
5

Flora made 3 withdrawals of $75 each from her bank account. What was the overall change in her account?

Mathematics
1 answer:
sertanlavr [38]3 years ago
7 0
The answer will be $-225
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Jade has $22 to spend at the grocery store. He is going to buy bags of Takis that cost $4 each and one box of Oreos that costs $
Savatey [412]

Answer:

4 bags of takis

Step-by-step explanation:

take the $22 and subtract the $3.50 for the oreos, this leaves you with $18.50.

now, take the $18.50 and divide that by $4 (the amount takis cost) and you will find out how many bas he will he able to buy.

18.50/4 = 4.6 he will be able to buy only 4 bags and will have $2.50 left over

8 0
2 years ago
West Virginia math glencone course 2 volume 1 page 191
Step2247 [10]

Answer:

Im not sure but I think its -5

7 0
2 years ago
Find the common difference of the sequence shown 1/6, 1/4, 1/3
Damm [24]

1/4 - 1/6 = (6-4)/24 = 2/24 = 1/12
1/3 - 1/4 = (4-3)/12 = 1/12



7 0
3 years ago
Read 2 more answers
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
Viefleur [7K]

Answer:

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

Suppose a sample of 1537 tenth graders is drawn. Of the students sampled, 1184 read above the eighth grade level. So 1537 - 1184 = 353 read at or below this level. Then

n = 1537, \pi = \frac{353}{1537} = 0.2297

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2297 - 1.96\sqrt{\frac{0.2297*0.7703}{1537}} = 0.2087

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2297 + 1.96\sqrt{\frac{0.2297*0.7703}{1537}} = 0.2507

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).

7 0
3 years ago
10points!<br> will make brainliest for correct answer <br> -8 1/3 + (- 1/6)
pentagon [3]

Answer: -8 1/2 I think

Step-by-step explanation:

First you make -8 1/3 a improper fraction

than you find common denominators

and you keep the sign of the biggest number

simplify if possible

8 0
3 years ago
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