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3 years ago

If a1=4 and an=(an-1)^2 + 5 then find the value of a3.

Mathematics

1 answer:

baherus [9]3 years ago

5 0

Answer:

446

Step-by-step explanation:

a2=16+5=21 then a3=441+5=446

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For what value of d would the statement 6d = 30 be true?

hram777 [196]

Answer:

Step-by-step explanation:

5(6) = 30

6 0

3 years ago

Instructions: Find the equation of the line through point (−4,1) and parallel to y=−12x−2. Use a forward slash (i.e. "/") for fr

USPshnik [31]

Answer:

y = - 12x - 47

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 12x - 2 ← is in slope- intercept form

with slope m = - 12

Parallel lines have equal slopes, thus

y = - 12x + c ← is the partial equation

To find c substitute (- 4, 1 ) into the partial equation

1 = 48 + c ⇒ c = 1 - 48 = - 47

y = - 12x - 47 ← equation of parallel line

7 0

4 years ago

Help me plz i need the answer

Setler [38]

1st one is 0

2nd one is -3

3rd one is -2

4th one is 5

Combine like terms, isolate the variable, and make the slope of the variable 1 to find all the answers.

8 0

3 years ago

The mayor gets elected every four years. Treasurer gets elected every six years. Both were elected this year. How many years bef

aleksandrvk [35]

<h3>There are 11 years before both the elections happen in the same year.</h3>

Step-by-step explanation:

The mayor gets selected once in every 4 years.

So, the number of years the mayor elections takes place

= 1, 4 ,8, 12, 16, 20, 24, 28,....

Now, the Treasurer gets selected once in every 6 years.

So, the number of years the Treasurer elections takes place

= 1, 6, 12, 18, 24, 30

Now,as we can see from both statements, the year in which both elections happen are the common factors of 4 and 6.

The first common factor of 4 and 6 is 12.

So,in twelfth year both elections happen in the same year again.

Hence, there are 11 years before the elections happen in the same year.

4 0

3 years ago

The Chair of the Operations Management Department at Quality University wants to construct a p-chart for determining whether the

mestny [16]

Answer:

A) Professor A failure proportion = 0.12 ; B) Average = 0.1 ; C) σ = 0.055

Step-by-step explanation:

1) Proportion of failures for Prof A : Failure / Total

= 12 / 100 = 0.12

2) Proportion of failures for Prof B : 1/ 100 = 0.01

Proportion of failures for Prof C : 11 / 100 = 0.11

Proportion of failures for Prof D = 16 / 11 = 0.16

Average proportional failure for all instructors :-

[ Prop (prof A) + Prop (prof B) + Prop (prof C) + Prop (prof D) ] / 4

(0.12 + 0.01+ 0.11 + 0.16 ) / 4 = 0.4 / 4 = 0.1

3) Standard Deviation (σ) = √ Σ (x - x')^2 / n , where x' = mean = 0.1

x x - x' (x - x')^2

0.12 0.02 0.0004

0.01 -0.09 0.0081

0.11 0.01 0.0001

0.16 0.06 0.0036

Σ = 0.0122

σ = √ 0.0122/ 4 = √0.00305 = 0.055

6 0

3 years ago