To solve this, you need to divide 127.5 by 51:
127.5/51 = 2.5
To find the percent, multiply 2.5 by 100:
2.5 x 100% = 250%
So 127.5 is 250% of 51
Answer:
-10.2c + 2.2
Step-by-step explanation:
To make things less complicated, write down everything separate from the other. Then group together the intercepts and the coefficients into separate groups. After that, add them up separately in a format to where it will look like basic addition.
Hope this helps. I also apologize for any errors.
Answer:
We conclude that the mean nicotine content is less than 31.7 milligrams for this brand of cigarette.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 31.7 milligrams
Sample mean, 
= 28.5 milligrams
Sample size, n = 9
Alpha, α = 0.05
Sample standard deviation, s = 2.8 milligrams
First, we design the null and the alternate hypothesis
We use One-tailed t test to perform this hypothesis.
Formula:
Putting all the values, we have
Now, 
Since,
We fail to accept the null hypothesis and accept the alternate hypothesis. We conclude that the mean nicotine content is less than 31.7 milligrams for this brand of cigarette.
Answer:
<u>1/20 of the patrons at Joe's restaurant are expected to be male and out of town.</u>
Step-by-step explanation:
1. Let's review all the information provided for solving this question:
Proportion of patrons that are male at Joe's restaurant = 1/4
Proportion of patrons that are from out of town at Joe's restaurant = 1/5
2. What proportion would you expect to be male and out of town?
For finding the proportion of the patrons, that would be male and that would be from out of town, we do this calculation:
Proportion of patrons that are male at Joe's restaurant * Proportion of patrons that are from out of town at Joe's restaurant
<u>1/4 * 1/5 = 1/20 </u>
<u>It means that 1/20 of the patrons at Joe's restaurant are expected to be male and out of town.</u>
If two angles are equal, then the two angles are obtuse.
