So k=1000 like 4k=4 000 so 6/7 of a thousnad =0.857142857 so times 6=0.857142857
The area of the house is the amount of space on the house.
- The length of the addition is x + 20
- The area of the original house is
<h3>The length of the addition</h3>
The area of the addition is given as:
Expand
Factorize
Factor out x + 20
The width of the addition is x - 10.
Hence, the length of the addition is x + 20
<h3>The area of the original house</h3>
The dimension of the original house is
x + 20 by x + 10
So, the area is:
Expand
This gives
Hence, the area of the original house is
Read more about areas at:
brainly.com/question/24487155
F is located on the numbe<u>r 4.5</u><u> </u>on the number line.
<h3>
</h3><h3>
Where does point F lie on the number line?</h3>
We know that point D is at -6
Point E is at 8.
Point F is between D and E, such that the ratio:
DF:FE is 3:1
So if we divide the distance between D and E in 4 parts, 3 of these parts are DF, and one of these parts is FE.
First, the distance between E and D is:
distance = 8 - (-6) = 14 units.
Now, if we divide that by 4, we get:
14/4 = 3.5
Then we have:
DF = 3*(3.5) = 10.5
This means that F is at 10.5 units to the right of D, then:
F = D + 10.5 = -6 + 10.5 = 4.5
F is located on the numbe<u>r 4.5</u><u> </u>on the number line.
If you want to learn more about ratios:
brainly.com/question/2328454
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Add them. Pentagram interior angle is 540. 105+101+112+113=431. 540-431=109 Hence, 109 is the answer. Please brainliest.
<u><em>Answer:</em></u>
SAS
<u><em>Explanation:</em></u>
<u>Before solving the problem, let's define each of the given theorems:</u>
<u>1- SSS (side-side-side):</u> This theorem is valid when the three sides of the first triangle are congruent to the corresponding three sides in the second triangle
<u>2- SAS (side-angle-side):</u> This theorem is valid when two sides and the included angle between them in the first triangle are congruent to the corresponding two sides and the included angle between them in the second triangle
<u>3- ASA (angle-side-angle):</u> This theorem is valid when two angles and the included side between them in the first triangle are congruent to the corresponding two angles and the included side between them in the second triangle
<u>4- AAS (angle-angle-side):</u> This theorem is valid when two angles and a side that is not included between them in the first triangle are congruent to the corresponding two angles and a side that is not included between them in the second triangle
<u>Now, let's check the given triangles:</u>
We can note that the two sides and the included angle between them in the first triangle are congruent to the corresponding two sides and the included angle between them in the second triangle
This means that the two triangles are congruent by <u>SAS</u> theorem
Hope this helps :)
