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Serga [27]
3 years ago
11

Please Help Question; What is the value of x?

Mathematics
1 answer:
Maksim231197 [3]3 years ago
6 0

Answer:

x+5/30 = 16/20

20x+100=480

20x=380

x=19

Step-by-step explanation:

x+5/30 = 16/20

20x+100=480

20x=380

x=19

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Reduce the Fractions 15/9to its Lowest Terms
KatRina [158]

\large\bf{\red{  \implies}} \tt \:   \cancel\frac{15}{9}   \\

\large\bf{\red{  \implies}} \tt \:   \frac{5}{3}  \\

Decimal Form - 1.6667

6 0
2 years ago
Solve the equation of exponential decay.
BabaBlast [244]

Answer:

$9,220,000(0.888)^t

Step-by-step explanation:

Model this using the following formula:

Value = (Present Value)*(1 - rate of decay)^(number of years)

Here, Value after t years = $9,220,000(1 -0.112)^t

          Value after t years =  $9,220,000(0.888)^t

3 0
3 years ago
A family is measuring its house in order to figure out how much paint will be
tester [92]

Answer: How much paint

The independent variable is the measuring of the house

5 0
3 years ago
Find the length of the second leg of the triangle round to the nearest hundredth
horsena [70]

Answer:

\displaystyle \frac{3\sqrt{230}}{5}

Step-by-step explanation:

Use the Pythagorean Theorem:

\displaystyle a^2 + b^2 = c^2 \\ \\ 9,7^2 + b^2 = 13,3^2; \sqrt{82,8} = \sqrt{b^2} \\ \\ \frac{3\sqrt{230}}{5}\:[or\:9,0994505329...] = b

So, you have this:

\displaystyle 9,1 ≈ b

I am joyous to assist you at any time.

7 0
2 years ago
Great Amusements Park has been raising its ticket prices every year, as shown in the table below
Fiesta28 [93]
1.)

Between year 0 and year 1, we went from $50 to $55.

$55/$50 = 1.1

The price increased by 10% from year 0 to year 1.

Between year 2 and year 1, we went from $55 to $60.50.

$60.50/$55 = 1.1

The price also increased by 10% from year 1 to year 2. If we investigate this for each year, we will see that the price increases consistently by 10% every year.

The sequence can be written as an = 50·(1.1)ⁿ

2.) To determine the price in year 6, we can use the sequence formula we established already.

a6 = 50·(1.1)⁶ = $88.58

The price of the tickets in year 6 will be $88.58.
4 0
3 years ago
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