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Dmitrij [34]
3 years ago
14

Which equation in point-slope form contains the point (4, –1) and has slope 3?

Mathematics
1 answer:
Andrew [12]3 years ago
4 0

Answer:

y+1=3(x-4)

Step-by-step explanation:

Hi there!

We are given a slope of 3 and a point (4,-1).

We need to find the equation of the line in point-slope form

Point-slope form is given as y-y1=m(x-x1), where m is the slope, and (x1,y1) is a point

We have all of the needed information to substitute into the formula

First, let's label the values of everything to avoid any confusion

m=3

x1=4

y1=-1

now substitute into the formula *remember, the formula has SUBTRACTION, and we have a NEGATIVE number, so we'll end up subtracting a negative*

y--1=3(x-4)

simplify

y+1=3(x-4)

That's it!

Hope this helps :)

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3 years ago
Solve these equations for the variable.<br> (4p-4)(13p+27)
kondaur [170]

Answer:

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Step-by-step explanation:

We can solve this first by expanding, giving us a quadratic equation in the usual ax² + bx + c format, then solving that for p:

(4p - 4)(13p + 27) = 0

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52p² + 52p - 108 = 0

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