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alexdok [17]
3 years ago
11

Suppose that an Individual has a body fat percentage of 18.8% and weighs 127 pounds. How many pounds of her weight is made up of

fat? Round your answer
to the nearest tenth.
pounds
Mathematics
1 answer:
Phoenix [80]3 years ago
8 0

Answer:

14.8 pounds

Step-by-step explanation:

Here, we want to get the actual value made of fat from the body weight

What we have to do here is to multiply the percentage by the body weight

Mathematically, we have this as;

18.8% of 127 pounds

= 18.8/100 * 127 = 14.80 pounds

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Decrease 1.25 km by 0.6%​
Anna35 [415]

Answer:

124250cm, 1242.5m or 1.2425km

Step-by-step explanation:

0.6% = 6/100

6/100 = 0.006

0.006*1.25 = 0.0075

1.25km = 1250m = 125000cm

0.0075km = 7.5m = 750cm

125000 - 750 = 124250

Therefore:

The answer is 124250cm, 1242.5m or 1.2425km

Sub to oTechz :)

4 0
2 years ago
Find what x is? 5×3>4+8+x a good help for your brain! ​
MaRussiya [10]

Answer:

x = 2.25 or any number greater

Step-by-step explanation:

5x3 > 4 + 8 + x

Make them equal to each other to get x

5x3 = 4 + 8 + x

(5x)(3) = 12 + x

- x - 3   - 3  - x

4x = 9

\frac{4x}{4} = \frac{9}{4}

x = 2.25

Once you get x plug it in to get the truth of the expression

6 0
3 years ago
Machine M, working alone at its constant rate, produces x widgets every 4 minutes. Machine N, working alone at its constant rate
Harman [31]

Answer:

Yes

Step-by-step explanation:

Given that Machine M, working alone at its constant rate, produces x widgets every 4 minutes. Machine N, working alone at its constant rate, produces y widgets every 5 minutes.

When both machines work for 20 minutes

Machine A would produce = \frac{20}{4} =5 widget and

Machine B would produce = \frac{20}{5} =4 widgets

So we can say that Machine A would produce more widgets than Machine N at that time.

Answer is Yes

8 0
3 years ago
If y varies inversely with the square of x, and y=6 when x=4, find y when x=0.1
sergejj [24]

Answer:

9600

Step-by-step explanation:

y varies inversely with the square of x

y=k/(x^2)

for some non-zero constant k

y=6 when x=4

6=k/(4^2)

k=96

y=96/(x^2)

x=0.1

y=96/(0.1^2)

y=9600

8 0
2 years ago
Compute the value of the discriminant and give the number of real solutions of the quadratic equation.
Sergio039 [100]
-2x^2+6x-3=0 \\ \\
a=-2 \\ b=6 \\ c=-3 \\ \Delta=b^2-4ac=6^2-4 \times (-2) \times (-3)=36-24=12

The value of the discriminant is 12.
Since the discriminant is greater than zero, the equation has two real solutions.
4 0
3 years ago
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