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Fofino [41]
3 years ago
13

Anyone know 72 through 75?

Mathematics
1 answer:
maw [93]3 years ago
4 0

Answer:

Ans

Step-by-step explanation:

72. 3x+5y

73. 3pq

74. 8a+8b

75. 4x^2+7x

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Evaluate 3 square root 125/100?<br> What is the answer plz help thx
vlabodo [156]
The answer to the question

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It's solving multi-step inequalities
babymother [125]
H is less than or equal to 35

Just simplify each side and solve for the variable. 
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3 years ago
Yolonda withdrew 60 dollars from her checking account.Write a signed number to represent this change in her account.
JulsSmile [24]

Answer:

$ 60.00

Step-by-step explanation:

.

8 0
2 years ago
A salesman travelled 2/5 of his journey before lunch and 3/8 of his journey after lunch.
AysviL [449]
2/5+3/8= 31/40 therefore he still has 9/40 to go.
to get this you multiply the two denominators together
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to get the final
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7 0
3 years ago
What are the coordinates of the orthocenter of △JKL with vertices at J(−4, −1) , K(−4, 8) , and L(2, 8) ?
Sati [7]

<u>Answer-</u>

<em>The coordinates of the orthocenter of △JKL is (-4, 8)</em>

<u>Solution-</u>

The orthocenter is the point where all three altitudes of the triangle intersect. An altitude is a line which passes through a vertex of the triangle and is perpendicular to the opposite side.

For a right angle triangle, the vertex at the right angle is the orthocentre of the triangle.

Here we are given the three vertices of the triangle are  J(-4,-1), K(-4,8) and L(2,8)

If the triangle JKL satisfies Pythagoras Theorem, then triangle JKL will be a right angle triangle.

Applying distance formula we get,

JK^2= (-4+4)^2+ (8+1)^2=0+81=81\\\\KL^2= (-4-2)^2+ (8-8)^2=36+0=36\\\\JL^2= (-4-2)^2+(8+1)^2=36+81=117

As,

\Rightarrow 117=81+36

\Rightarrow JL^2=JK^2+KL^2

\Rightarrow \text{JKL is a right angle triangle}

\Rightarrow \angle K=90^{\circ}

Therefore, the vertex at K (-4, 8) is the orthocentre.

3 0
3 years ago
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