prove that cos theta by 1 minus tan theta + sin theta by 1 minus cot theta equal to sin theta + cos theta
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Answer:
see explanation
Step-by-step explanation:
In an arithmetic sequence the common difference d is
d = a₂ - a₁ = 10 - 8 = 2
To obtain the next term in the sequence add d to the previous term, that is
a₅ = 14 + 2 = 16
a₆ = 16 + 2 = 18
a₇ = 18 + 2 = 20
The next 3 terms in the sequence are 16, 18, 20
The n th term equation for an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 8 and d = 2, thus
= 8 + 2(n - 1) = 8 + 2n - 2 = 2n + 6