2/5y + 3/5 did that work?
Answer:
p²q³ + pq and pq(pq² + 1)
Step-by-step explanation:
Given
3p²q² - 3p²q³ +4p²q³ -3p²q² + pq
Required
Collect like terms
We start by rewriting the expression
3p²q² - 3p²q³ +4p²q³ -3p²q² + pq
Collect like terms
3p²q² -3p²q² - 3p²q³ +4p²q³ + pq
Group like terms
(3p²q² -3p²q²) - (3p²q³ - 4p²q³ ) + pq
Perform arithmetic operations on like terms
(0) - (-p²q³) + pq
- (-p²q³) + pq
Open bracket
p²q³ + pq
The answer can be further simplified
Factorize p²q³ + pq
pq(pq² + 1)
Hence, 3p²q² - 3p²q³ +4p²q³ -3p²q² + pq is equivalent to p²q³ + pq and pq(pq² + 1)
Answer:
5m+30+2n
Step-by-step explanation:
3m+30 and - 2m+2n
5m+30+2n
Answer:
26.3
It’s really simple actually
Answer:
95 ; 105
Step-by-step explanation:
Let :
Aanya's time = x
Krish's time = x + 10
Together = 50
Hence
Aanya's rate = 1/x
Krish's rate = 1/(x + 10)
Together rate = 1/50
Hence,
1/x + 1/(x + 10) = 1 / 50
((x + 10) + x) / x(x + 10) = 1/ 50
(2x + 10)/ x² + 10x = 1/50
50(2x + 10) = x² + 10x
100x + 500 = x² + 10x
x² + 10x - 100x - 500 = 0
x² - 90x - 500 = 0
Using the quadratic equation solver :
x = 95.24 ; x = - 5.24
Time can't be negative
Hence, x = 95 (nearest minute)
It takes Aanya 95 minutes Alone a ND
Krishna (95 + 10) = 105 minutes alone
