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Neko [114]
3 years ago
13

prove that cos theta by 1 minus tan theta + sin theta by 1 minus cot theta equal to sin theta + cos theta​

Mathematics
1 answer:
Sindrei [870]3 years ago
3 0

Here is the answer for prove that cos theta by 1 minus tan theta + sin theta by 1 minus cot theta equal to sin theta + cos theta

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A mixture of 60 liters of paint is 25% red tint, 30% yellow tint and 45% water. 9 liters of yellow tint are added to the origina
Jlenok [28]

The percentage of yellow tint in the new mixture will be 39.1304...%

<em><u>Explanation</u></em>

A mixture of 60 liters of paint is 25% red tint, 30% yellow tint and 45% water.

So, the amount of yellow tint =(60*0.30)liters= 18 liters.

Now, 9 liters of yellow tint are added to the original mixture. So, the <u>total amount of yellow tint in the new mixture</u> will be: (18+9)liters= 27 liters.

And the <u>total amount of the new mixture</u> will be: (60+9)liters= 69 liters.

So, the percentage of yellow tint in the new mixture =\frac{27}{69}\times 100\% = 39.1304... \%

6 0
3 years ago
Find two other pairs of polar coordinates of the given polar coordinate, one with r &gt; 0 and one with r &lt; 0.
navik [9.2K]

Answer:

A) (5, 7π/4):   (5, 15π/4) and (-5, 3π/4)

B) (−6, π/2):   (−6, 5π/2) and (6, -π/2)

C) (5, −2):       (5, 2π-2) and (-5, -π-2)

Step-by-step explanation:

To find pair of coordinates for (r>0), add 2π to corresponding θ. For (r<0) subtract π from given angle to find second pair of coordinate.

A)  (5, 7π/4)

For (r>0)

θ =  7π/4 + 2π

θ =  15π/4

Point is (5, 15π/4)

For (r<0)

θ =  7π/4 - π

θ =  3π/4

Point is (-5, 3π/4)

As it can be seen in Fig 1

(5, 7π/4)=(5, 15π/4)=(-5, 3π/4)

B)  (−6, π/2)

For (r>0)

θ =  π/2 + 2π

θ =  5π/2

Point is (6, 5π/2)

For (r<0)

θ =  π/2 - π

θ =  -π/2

Point is (-6, -π/2)

As shown in fig 2

(-6, π/2) = (6, 5π/2) = (-6, -π/2)

C) (5, −2)

For (r>0)

θ =  -2 + 2π

Point is (5, 2π-2)

For (r<0)

θ =  -2 - π

Point is (-5, -π)

As shown in Fig. 3

(5, −2) = (5, 2π-2) = (-5, -π)

5 0
4 years ago
The product of two consecutive positive odd numbers is 195.By constructing a quadratic equation and solving it, find the two num
Tomtit [17]

Step-by-step explanation:

x = one odd number

the second odd number is (x+2), as both are consecutive.

so,

x × (x + 2) = 195

x² + 2x = 195

x² + 2x - 195 = 0

the formula to solve this is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 1

b = 2

c = -195

x = (-2 ± sqrt(4 - 4×1×-195))/(2×1) =

= (-2 ± sqrt(4 + 4×195))/2 = (-2 ± sqrt(784))/2 =

= (-2 ± 28)/2 = -1 ± 14

x1 = -1 + 14 = 13

x2 = -1 - 14 = -15 which is invalid as the numbers are positive.

so, the two numbers are 13 and 15.

5 0
3 years ago
Suppose that the mean and standard deviation of the scores on a statistics exam are 78 and 6.11, respectively, and are approxima
kiruha [24]

Answer:

0.7422 = 74.22% of scores are above 74.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 78, \sigma = 6.11

Calculate the proportion of scores above 74.

This is 1 subtracted by the pvalue of Z when X = 74. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{74 - 78}{6.11}

Z = -0.65

Z = -0.65 has a pvalue of 0.2578

So 1-0.2578 = 0.7422 = 74.22% of scores are above 74.

8 0
4 years ago
Can anyone help me?
bija089 [108]

Answer:

Step-by-step explanation:

y= -833.3+42,000

29,500

6 0
3 years ago
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