2)Perimeter=28 rounded to 30. Area=48 rounded up to 50.
There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
PEMDAS
yo might be tricked to do 2(-7) but that's multiplcation
so expoments
(-6)^2=36
now we have
36/12-2(-7)
mulitipictioan or division whicever comes first
division
36/12=3
multiplcation 2(-7)=-14
now we have
3-(-14)
3+14
17
answer is 17
I think it’s A I hope it helps
Height = 9 ft
Radius = Diameter/2 = 12/2 = 6 ft
Volume of a cone = 1/3πr²h
= 2/3 × 3.14 × 6 × 6 × 9
= 339.12 ≈ 339.1 cubic foot.