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GaryK [48]
3 years ago
15

Suppose hamburger buns cost $1.79 per package. how much would it cost to buy 6 packages?

Mathematics
2 answers:
Inessa [10]3 years ago
6 0

Answer:

$10.74 or C.

Step-by-step explanation:

First multiply the total cost of a single package of buns by the number you want, in this case 6.

1.79 x 6 = 10.74


borishaifa [10]3 years ago
3 0

Answer: your answer is 10.74 or C


Step-by-step explanation: 1.79x6= 10.74

                                                 


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Andrés, in his shop, stores the buttons in bags. In box A, he has bags of 24 buttons each with no buttons left. In box B, he has
Lynna [10]

Answer:

120 buttons in each box

Step-by-step explanation:

What you are looking for is the least common multiple. List out what the multiples of each number are and when ever you find two numbers that match you have your answer.

5 0
2 years ago
Big Mack buys meat for the family reunion cookout. He needs to buy 11 packagesof meat. A package of hotdogs costs $2.59, and a p
IgorC [24]

Hello!

Let's write some important information contained in the exercise:

• hotdogs: $2.59 (,x,)

,

• hamburgers: $5.29 (,y,)

He needs 11 packages. Let's write it:

• x + y = 11

He spent a total of $39.29. We can write it as:

• 2.59x + 5.29y = 39.29

Now, let's solve these two equations as a linear system:

\begin{cases}x+y=11\text{ equation A} \\ 2.59x+5.29y=39.29\text{ equation B}\end{cases}

First, let's isolate x in equation A:

\begin{gathered} x+y=11 \\ x=11-y \end{gathered}

Now, we will replace where's x by 11-y in equation B:

\begin{gathered} 2.59x+5.29y=39.29 \\ 2.59(11-y)+5.29y=39.29 \\ 28.49-2.59y+5.29y=39.29 \\ -2.59y+5.29y=39.29-28.49 \\ 2.7y=10.8 \\ y=\frac{10.8}{2.7} \\  \\ y=4 \end{gathered}

As I called the hamburgers as 'y', we know that he bought 4 packages of hamburgers.

5 0
1 year ago
What type of proportion is shown in 12 : 4 = 24 : 8?​
Dmitry [639]

Answer:

3:1

Step-by-step explanation:

7 0
3 years ago
Find the quadratic function y=​f(x) whose graph has a vertex ​(−3​,4​) and passes through the point ​(−7​,0). Write the function
olganol [36]

Answer:

Step-by-step explanation:

This is a parabola since a quadratic is a parabola.  The standard form for a parabola is y = ax² + bx + c

but before we do that, we will use the vertex form, since it will make our work easier at the beginning.  

First and foremost, when we plot the vertex and the given point, the vertex is higher up than is the point; that means that this parabola opens upside down, and its vertex form will be

y=-|a|(x - h)² + k

The absolute value is out in front of the a, so we know that the value of a is positive, but the quadratic itself is negative (upside down) and we will find that math takes care of that negative that needs to be out front.  So we need to solve for a by filling in the x, y, h, and k values from the point and the vertex:  x = -7, y = 0, h = -3, k = 4

0 = a(-7 - (-3))² + 4 and

0 = a(-7 + 3)² + 4 and

0 = a(-4)² + 4 and

0 = a(16) + 4 and

0 = 16a + 4 and

-4 = 16a so

a=-\frac{1}{4}

Now that we know a, we can plug it back into the vertex form and then put it into standard form from there.

y=-\frac{1}{4}(x+3)^2+4

Now we will FOIL out what's inside the parenthesis to get

y=-\frac{1}{4}(x^2+6x+9)+4

Simplify by distributing the -1/4 into the parenthesis:

y=-\frac{1}{4}x^2-\frac{3}{2}x-\frac{9}{4}+4

Combine like terms to get

y=-\frac{1}{4}x^2-\frac{3}{2}x+\frac{7}{4}

And there you go!

5 0
3 years ago
These box plots show daily low temperatures for a sample of days in two
Mumz [18]

Answer:

C. The distribution for town A is symmetric, but the distribution for

town B is negatively skewed.

Step-by-step Explanation:

From the box plots attached in the diagram below, which shows data of low temperatures for town A and town B for some days, we can compare the shapes of the box plot by visually analysing both box plots and how the data for each town is distributed.

=> For town A, the shape of the box plot is symmetric because both quartiles seem equal, and the median also divides the rectangular box into two equal halves. Both whiskers also appear to be of equal lengths.

The box plot for Town A takes a symmetric shape, and this shows a typical normal distribution of data.

=> On the other hand, Town B data distribution is different. The median seem close to the top half of the box and does not divide the box into equal halves. This shows the distribution is skewed. Since the whisker is shorter from the upper end of the box to the left side, we can infer that the distribution for Town B is skewed to the left, and it is negatively skewed.

=> The right comparison of the shapes of the box plots is "C. The distribution for town A is symmetric, but the distribution for town B is negatively skewed."

7 0
3 years ago
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