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vfiekz [6]
3 years ago
6

How many pieces of wire 3.6cm long can be cut from a coil of 1m long?What is the length of the piece left over?​

Mathematics
2 answers:
sp2606 [1]3 years ago
8 0

Answer:

We can get 27 pieces of wire 3.6 cm long and have a piece 7/9 cm left over

Step-by-step explanation:

Find the "unit length" by dividing 1 m by 3.6 cm:

  1 m

-----------

3.6 cm

Recall that 1 m = 100 cm.  Multiply the following by the conversion factor 100 cm / 1 m:

  1 m            100 cm

----------- * ----------------- = 27,7777777...

3.6 cm            1 m

We can get 27 pieces of wire 3.6 cm long and have a piece 7/9 cm left over (verify this by dividing 7 by 9 on a calculator).

dybincka [34]3 years ago
4 0

Answer:

<h2><u>Solution</u><u> </u><u>:</u><u>-</u></h2>

Pieces can be cut = 1/3.6

Pieces can be cut = 0.27 m

100 cm = 1 m

0.27 m = 27 cm

Therefore,

The length remaining of wire is 27 cm (approximately)

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At a discount furniture store, there is a sale price of $550 for a couch
cestrela7 [59]

Answer:

594$ with sales tax

Step-by-step explanation:

550 + 44.00 = 594

5 0
3 years ago
The length of a rectangle is four times the width. The perimeter of the rectangle is 45 inches. Write a system of
Yakvenalex [24]

Answer:

81 square inches.

Step-by-step explanation:

Draw a diagram to represent what you know.

You don't know the values of the lengths so represent them algebraically.

You know the perimeter is 45 inches and that the perimeter is calculated by the sum of all of the sides of a shape.

You can rearrange to find the value of a side you've denoted as some unknown variable.

The area is given by the product of the sides. Express this algebraically and then input the value you found.

4 0
3 years ago
I don't even know where to start.
alexira [117]
Don't know if this helps but the small thing will fit in the big shape about 6 times
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7 0
3 years ago
Please find measure of angle s. PLEASE HELP FAST!!
Studentka2010 [4]

Answer:

27

Step-by-step explanation:

15x-31 = 9x+11

6x-31 = 11

6x = 42

x = 7

15x -31 + 9x + 11 + s = 180

15(7) -31 + 9(7) + 11  + s = 180

105 - 31 + 63 + 11 + s = 180

153 + s = 180

s = 27

8 0
3 years ago
The half life of radium is 1690 years. if 80 grams are present now, how much will be present in 830 years
Pachacha [2.7K]

Answer:

A(t) = amount remaining in t years

      = A0ekt, where A0 is the initial amount and k is a constant to                     be determined.  

Since A(1690) = (1/2)A0 and A0 = 80,

                we have 40 = 80e1690k

                1/2 = e1690k

                ln(1/2) = 1690k

                k = -0.0004

So, A(t) = 80e-0.0004t

Therefore, A(430) = 80e-0.0004(430)

                           = 80e-0.172

                           ≈ 67.4 g

Step-by-step explanation:

5 0
2 years ago
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