The length of a rectangle is four times the width. The perimeter of the rectangle is 45 inches. Write a system of
1 answer:
Answer:
81 square inches.
Step-by-step explanation:
Draw a diagram to represent what you know.
You don't know the values of the lengths so represent them algebraically.
You know the perimeter is 45 inches and that the perimeter is calculated by the sum of all of the sides of a shape.
You can rearrange to find the value of a side you've denoted as some unknown variable.
The area is given by the product of the sides. Express this algebraically and then input the value you found.
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Answer:
Step-by-step explanation:
Let the 2 numbers be x and y
From the problem we have that
x * y = 600 and x + y = 59
From x + y = 59 -> x = 59 - y
Plug x = 59 - y to x * y = 600 we have
(59 - y) * y = 600
-> 59y - y^2 = 600
-> -y^2 + 59y - 600 = 0
-> y = or
Then we could plug the answers in and find x because x = 59 - y
Remark
If you don't start exactly the right way, you can get into all kinds of trouble. This is just one of those cases. I think the best way to start is to divide both terms by x^(1/2)
Step One
Divide both terms in the numerator by x^(1/2)
y= 6x^(1/2) + 3x^(5/2 - 1/2)
y =6x^(1/2) + 3x^(4/2)
y = 6x^(1/2) + 3x^2 Now differentiate that. It should be much easier.
Step Two
Differentiate the y in the last step.
y' = 6(1/2) x^(- 1/2) + 3*2 x^(2 - 1)
y' = 3x^(-1/2) + 6x I wonder if there's anything else you can do to this. If there is, I don't see it.
I suppose this is possible.
y' = 3/x^(1/2) + 6x
y' =
Frankly I like the first answer better, but you have a choice of both.
If you don't start exactly the right way, you can get into all kinds of trouble. This is just one of those cases. I think the best way to start is to divide both terms by x^(1/2)
Step One
Divide both terms in the numerator by x^(1/2)
y= 6x^(1/2) + 3x^(5/2 - 1/2)
y =6x^(1/2) + 3x^(4/2)
y = 6x^(1/2) + 3x^2 Now differentiate that. It should be much easier.
Step Two
Differentiate the y in the last step.
y' = 6(1/2) x^(- 1/2) + 3*2 x^(2 - 1)
y' = 3x^(-1/2) + 6x I wonder if there's anything else you can do to this. If there is, I don't see it.
I suppose this is possible.
y' = 3/x^(1/2) + 6x
y' =
Frankly I like the first answer better, but you have a choice of both.
Answer:
For this case if we want to conclude that the sample does not come from a normally distributed population we need to satisfy the condition that the sample size would be large enough in order to use the central limit theoream and approximate the sample mean with the following distribution:
For this case the condition required in order to consider a sample size large is that n>30, then the best solution would be:
n>= 30
Step-by-step explanation:
For this case if we want to conclude that the sample does not come from a normally distributed population we need to satisfy the condition that the sample size would be large enough in order to use the central limit theoream and approximate the sample mean with the following distribution:
For this case the condition required in order to consider a sample size large is that n>30, then the best solution would be:
n>= 30