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Stells [14]
3 years ago
13

The length of a rectangle is four times the width. The perimeter of the rectangle is 45 inches. Write a system of

Mathematics
1 answer:
Yakvenalex [24]3 years ago
4 0

Answer:

81 square inches.

Step-by-step explanation:

Draw a diagram to represent what you know.

You don't know the values of the lengths so represent them algebraically.

You know the perimeter is 45 inches and that the perimeter is calculated by the sum of all of the sides of a shape.

You can rearrange to find the value of a side you've denoted as some unknown variable.

The area is given by the product of the sides. Express this algebraically and then input the value you found.

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The perimeter of a triangle is 70 in. The shortest side is 11 in. less than the longest side. The middle side is 24 in. less tha
kondor19780726 [428]

Answer:

The sides are

6

inches,

8

inches and

10

inches

Explanation:

I'd suggest that the question should read 'The perimeter of a triangle is 24 inches. The longest side is 4 inches longer than the shortest side, and the shortest side is three-fourths the length of the middle side. How do you find the length of each side of the triangle?'

In this case the question can be answered. If

x

is the length of the middle side, then the shortest side is 3/4x and the longest side is 3/4x+4

x+3/4x+3/4x+4=24

10/4x=20

x=8

Then the shortest side is 6and the longest side is 10

Step-by-step explanation:

4 0
3 years ago
Brainliest if your correct
loris [4]

Answer:

it would be the last option

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
How many solutions does the following equation have? (5 points)<br> 4x+ 12 = 0
zhenek [66]
One solution ! Which is x=-3
8 0
3 years ago
Hiw ti factorise x*-16​
ra1l [238]
Im assuming the problem is x^2-16, which would be factored to (x-4)(x+4)
7 0
3 years ago
The area of a square is tripled by adding 10 cm to one dimension and 12 cm to the other. Determine the side length of the square
Rina8888 [55]
Area = length *width
A = x²
3x² = (x+10)(x+12)
3x² = x²+10x+12x+120
3x² = x²+22x+120
3x²-3x² = x²+22x+120-3x²
0 = -2x²+22x+120
Factor to solve for x: 
-2(x²-11x-60)
(x+4)(x-15)
x = -4  & x = 15 but we can't have a negative length so we eliminate 4. The length of the square is 15 cm.
4 0
3 years ago
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