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steposvetlana [31]
3 years ago
14

Find the value of the polynomial 2x^3y^3+3xy-3x^3y^3+x^2y-xy+2x^2y for x=-1 and y=2

Mathematics
1 answer:
avanturin [10]3 years ago
7 0

Answer:

10

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Step-by-step explanation:

<u>Step 1: Define</u>

2x³y³ + 3xy - 3x³y³ + x²y - xy + 2x²y

x = -1

y = 2

<u>Step 2: Evaluate</u>

  1. Substitute:                                                                                                2(-1)³(2)³ + 3(-1)(2) - 3(-1)³(2)³ + (-1)²(2) - (-1)(2) + 2(-1)²(2)
  2. Exponents:                                                                                                         2(-1)(8) + 3(-1)(2) - 3(-1)(8) + 1(2) - (-1)(2) + 2(1)(2)
  3. Multiply:                                                                                                             -16 - 6 + 24 + 2 - (-2) + 4
  4. Simplify:                                                                                                                -16 - 6 + 24 + 2 + 2 + 4
  5. Subtract:                                                                                                             -22 + 24 + 2 + 2 + 4
  6. Add:                                                                                                                    2 + 2 + 2 + 4
  7. Add:                                                                                                                      4 + 2 + 4
  8. Add:                                                                                                                   6 + 4
  9. Add:                                                                                                                     10
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