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sesenic [268]
3 years ago
12

Jonah need 28 seconds to fold 2 how long dose Jonah need to fold 5 shirts

Mathematics
2 answers:
Elden [556K]3 years ago
5 0

Answer:i think its 70

Step-by-step explanation: 28 divided by 2 equals 14, so you take 14 and multiply it by 5 instead of 2 and you'll get 70

statuscvo [17]3 years ago
4 0

Answer:

70 shirts

Step-by-step explanation:

First off, there are 5 shirts. 2 shirts take 28 seconds. If you divide 28 by 2, that means that each shirt takes 14 seconds.

5x14=70

Therefore, it takes 70 seconds to fold 5 shirts.

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A small water bottle holds 75% as much as a large water bottle.
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The answer is 48 units. You do 36 / 75% it is 48. You can also check your answer by doing 48 times 75%, which would equal 36.
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What is the correct answer?
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Using the numbers 1-12 each one time only, create four true statements
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6 0
3 years ago
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11. rewrite the function in the form y=a (1+r)*
Anettt [7]

Problem 10

The two functions <u>are inverses</u> of each other. Why? Because we can think of f(x) = (x-7)/(-2) as y = (x-7)/(-2).

Swap x and y to get x = (y-7)/(-2). Solving for y leads to y = -2x+7 showing that g(x) = -2x+7 is the inverse of f(x) = (x-7)/(-2). This process can be done in reverse to get the same result.

===================================================

Problem 11

y = a(6)^(t/2)

y = a( 6^(1/2) )^t

y = a(2.4494897)^t

y = a( b )^t

where b = 6^(1/2) = 2.4494897 approximately

Set b equal to 1+r and solve for r

1+r = 2.4494897

r = 2.4494897-1

r = 1.4494897

This rounds to about r = 1.45

The r value is the decimal form of the percentage, which means we move the decimal point over two spots to the right to get 145% approximately

Answers:

The equation is roughly y = a(1 + 1.4494897)^t

The growth rate is approximately 145%

===================================================

Problem 12

You have the correct answer. Nice work.

===================================================

Problem 13

You are very close to the correct answer. However, you're missing the base of the log.

The answer should be \log_{49}(343) = \frac{3}{2}. So you'll need to write in a small "49" under the log.

The general rule is that exponential equations in the form b^x = y are equivalent to the log version of \log_{b}(y) = x. For each equation, b is the base. The idea of logs is to isolate the exponent.

3 0
1 year ago
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