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inna [77]
3 years ago
7

What is the length of segment XY? 4.5 units /45 units /53 units 9 units

Mathematics
2 answers:
noname [10]3 years ago
8 0
It might be √53 because they are 7 squares away from each other ( I have the same question ) but Im not 100% sure..  
sergiy2304 [10]3 years ago
7 0

Answer: The correct option is (C) √53 units.

Step-by-step explanation:  We are given to find the length of the line segment XY in the graph.

We know that the length of a line segment is equal to the distance between its end points.

<u><em>DISTANCE FORMULA:</em></u> The distance between two points with co-ordiantes (a, b) ad (c, d) is given by

D=\sqrt{(c-a)^2+(d-b)^2}.

From the graph, we note that

the co-ordinates of the point X are (-4, 0) and the co-ordinates of the point Y are (3, 2).

Therefore, the distance between the points X and Y is given by

D\\\\=\sqrt{(3-(-4))^2+(2-0)^2}\\\\=\sqrt{7^2+2^2}\\\\=\sqrt{49+4}\\\\=\sqrt{53}.

So, the length of the line segment XY is √53 units.

Option (C) is correct.

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Do the three points lie on one line?
padilas [110]

Answer:

Yes. No graph paper.

Step-by-step explanation:

Let's say the 3 points are A, B, C.

If A, B and C lie on one line then m_{AB} = m_{BC} = m_{AC}

m_{AB} = \frac{y_{B}-y_{A} }{x_{B}-x_{A}} = \frac{2-6}{3-5} = \frac{-4}{-2} = 2\\m_{BC} = \frac{y_{C}-y_{B} }{x_{C}-x_{B}} = \frac{8-2}{6-3} = \frac{6}{3} = 2\\\\m_{AC} = \frac{y_{C}-y_{A} }{x_{C}-x_{A}} = \frac{8-6}{6-5} = \frac{2}{1} = 2\\\\

Hence, they lie on one line.

You don't need to use a graph paper to prove it.

4 0
2 years ago
What is going on<br>I am confused ​
nikdorinn [45]
?????? what do you mean
6 0
3 years ago
Read 2 more answers
The weekly amount spent by a small company for in-state travel has approximately a normal distribution with mean $1450 and stand
Llana [10]

Answer:

0.0903

Step-by-step explanation:

Given that :

The mean = 1450

The standard deviation = 220

sample mean = 1560

P(X > 1560) = P( Z > \dfrac{x - \mu}{\sigma})

P(X > 1560) = P(Z > \dfrac{1560 - 1450}{220})

P(X > 1560) = P(Z > \dfrac{110}{220})

P(X> 1560) = P(Z > 0.5)

P(X> 1560) = 1 - P(Z < 0.5)

From the z tables;

P(X> 1560) = 1 - 0.6915

P(X> 1560) = 0.3085

Let consider the given number of weeks = 52

Mean \mu_x = np = 52 × 0.3085 = 16.042

The standard deviation =  \sqrt {n \time p (1-p)}

The standard deviation = \sqrt {52 \times 0.3085 (1-0.3085)}

The standard deviation = 3.3306

Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.

Then;

Pr ( Y > 20) = P( z > 20)

Pr ( Y > 20) = P(Z > \dfrac{20.5 - 16.042}{3.3306})

Pr ( Y > 20) = P(Z >1 .338)

From z tables

P(Y > 20) \simeq 0.0903

7 0
3 years ago
ANSWER ALL THREE I WILL MAKE YOU THE BRAINLIEST EASY QUESTION
Anna35 [415]
Number 1 is 14/10 number 4 is 3 1/7 number 5 is 3 5/6
4 0
3 years ago
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Henry and 28 classmates go to the roller skating rink . Each van can hold 11 students . If all of the vans are full except one h
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You divide 29:11= 2 7/11
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so the answer is 7
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3 years ago
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