All categories

2 years ago

What is the vertex for the following quadratic? f(x)= 2x^2-12x+16

Mathematics

1 answer:

LenaWriter [7]2 years ago

7 0

Answer:

(3, -2)

Step-by-step explanation:

To find the vertex, put the equation into vertex form by completing the square

2(x^2 - 6x) + 16 [pulling out the 2]

2(x^2 - 6x + 9) - 18 + 16 [completing the square, you subtracted 2*9 = 18 so you also add 18]

2(x - 3)^2 - 2 [simplify the equation]

vertex is (3, -2)

You might be interested in

What are the intercepts? type an ordered pair.

Sunny_sXe [5.5K]

Answer: the x-intercepts are -4 and 2. The y-intercept(s) is 2

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Do midpoint riemann sums get more accurate with more rectangle.

LUCKY_DIMON [66]

Answer:

Yes

Step-by-step explanation:

They get more accurate as they have more data, the more data the more accurate it would be.

7 0

1 year ago

If the circumference of a circle is doubled, how does the diameter of the circle change?

jeyben [28]

diameter will be doubled

6 0

2 years ago

Which set of angle measures could form a triangle?

777dan777 [17]

Answer: C

Triangle=36+42+102=180

4 0

2 years ago

The faces on a number cube are labled 1,2,2,3,4, and 5the number cube is rolled 114 times how many times would you expect the nu

Mrac [35]

Given:

The faces on a number cube are labeled 1,2,2,3,4, and 5.

The number cube is rolled 114 times.

To find:

How many times would you expect the number 2 to appear?

Solution:

We have,

Total outcomes = 1,2,2,3,4, and 5.

Number of total outcomes = 6

Favorable outcomes = 2 and 2

Number of favorable outcomes = 2

The probability of getting 2 is:

$P(2)=\dfrac{\text{Number of favorable outcomes}}{\text{Number of total outcomes}}$

$P(2)=\dfrac{2}{6}$

$P(2)=\dfrac{1}{3}$

Now, the expected number of times when 2 to appear is:

$E(x)=114\times P(2)$

$E(x)=114\times \dfrac{1}{3}$

$E(x)=38$

Therefore, the expected number of times is 38.

4 0

2 years ago