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2 years ago

Which expression is equal to (x+2)(x−4)(x−4)(x+4)?

Mathematics

1 answer:

dimaraw [331]2 years ago

8 0

Answer:Since the expression on each side of the equation has the same denominator, the numerators must be equal.

Take the square root of both sides of the equation to eliminate the exponent on the left side.

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The complete solution is the result of both the positive and negative portions of the solution.

Tap for more steps...

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Exclude the solutions that do not make

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true.

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Step-by-step explanation:

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rusak2 [61]

Answer:

This question does not make since.

Step-by-step explanation:

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3 years ago

Ill mark brainlist plss

Harlamova29_29 [7]

Answer:

6/12

Step-by-step explanation:

the last one

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2 years ago

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9-c=-13.help......algebra

Ksivusya [100]

9 - c = -13
-c = -13 - 9
-c = - 22
c = 22 <===

3 0

3 years ago

Solve <img src="https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B1%7D%7Bp%7D%20%2B%20%5Cdfrac%7B1%7D%7Bq%7D%20%2B%20%5Cdfrac%7B1%7D

Nostrana [21]

Answer:

$\displaystyle \begin{cases} \displaystyle {x} _{1} = - p \\ \displaystyle x _{2} = - q \end{cases}$

Step-by-step explanation:

we would like to solve the following equation for x:

$\displaystyle \frac{1}{p} + \frac{1}{q} + \frac{1}{x} = \frac{1}{p + q + x}$

to do so isolate $\frac{1}{x}$ to right hand side and change its sign which yields:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{1}{p + q + x} - \frac{1}{x}$

simplify Substraction:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{x - (q + p + x)}{x(p + q + x)}$

get rid of only x:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{ - (q + p )}{x(p + q + x)}$

simplify addition of the left hand side:

$\displaystyle \frac{q + p}{pq} = \frac{ - (q + p )}{x(p + q + x)}$

divide both sides by q+p Which yields:

$\displaystyle \frac{1}{pq} = \frac{ -1}{x(p + q + x)}$

cross multiplication:

$\displaystyle x(p + q + x) = - pq$

distribute:

$\displaystyle xp + xq + {x}^{2} = - pq$

isolate -pq to the left hand side and change its sign:

$\displaystyle xp + xq + {x}^{2} + pq = 0$

rearrange it to standard form:

$\displaystyle {x}^{2} + xp + xq + pq = 0$

now notice we end up with a quadratic equation therefore to solve so we can consider factoring method to use so

factor out x:

$\displaystyle x( {x}^{} + p ) + xq + pq = 0$

factor out q:

$\displaystyle x( {x}^{} + p ) +q (x + p)= 0$

group:

$\displaystyle ( {x}^{} + p ) (x + q)= 0$

by Zero product property we obtain:

$\displaystyle \begin{cases} \displaystyle {x}^{} + p = 0 \\ \displaystyle x + q= 0 \end{cases}$

cancel out p from the first equation and q from the second equation which yields:

$\displaystyle \begin{cases} \displaystyle {x}^{} = - p \\ \displaystyle x = - q \end{cases}$

and we are done!

3 0

2 years ago

What is the area of a parallelogram that has a height of 2 1/2 inches and a base of 7 inches

crimeas [40]

Answer:

17 1/2 in²

Step-by-step explanation:

a=l×w

or in this case a=h×b

2 1/2×7= 17 1/2 in²

5 0

2 years ago