That's not a linear system, but you have an awesome school system for giving you this problem.

Multiply by 6xy to clear the fractions.

That's a second degree equation, also known as a conic. That one happens to be a hyperbola.


Let's clear the fractions from the second equation, multiplying out common denominator xy:


We are being asked to find the meet of two hyperbolas, so we expect two answers, a quadratic equation.
Substituting,





We have to rule out x=0 because it's in the denominator.


Answer: (44/19, 33/20)
Answer:
3/13
Step-by-step explanation:
8/13 subtract by 5/13. If the denominator is the same, you keep it, don't change it. Just subtract the numerator.
Make sure to simplify, if it is already simplified that will be the answer.
Answer:

Step-by-step explanation:
First Rectangle:

Second Rectangle:


Answer:

Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
we know that
In the right triangle ABC
----> by SOH (opposite side divided by the hypotenuse)
substitute the given values


Area is square units, so the new area would be the scale factor squared:
Scale factor is 2, so the area would increase by 2^2 = 4
The answer is B.4