Yes. That statement is true.
For example in : (1/2) divided by (3/4), you would invert 3/4 to make 4/3 and change the divide symbol to the multiply symbol. Becoming:
(1/2) multiplied by (4/3)<em> = </em><em>(1/2) divided by (3/4) = 0.66r</em>
Answer:
x = 12
Step-by-step explanation:
First, eliminate the fractional coefficient 1/2, by multiplying all three terms by 2:
-24 + x = -12
Adding 24 to both sides isolates x: x = -12 + 24, or x = 12
Count the total number of students who prefer fiction novels: In 9th grade there are 35, in 10th grade there are 52, so there are 87 students who prefer fictions. The proportion of 10th grade students out of these 87 students is 52/87=0.60 approximately.
Here's how to convert 0.16666 to a fraction...
There is not much that can be done to figure out how to write 0.16666 as a fraction, except to literally use what the decimal portion of your number, the .16666, means.
Since there are 5 digits in 16666, the very last digit is the "100000th" decimal place.
So we can just say that .16666 is the same as 16666/100000.
The fraction 16666/100000 is not reduced to lowest terms. We can reduce this fraction to lowest
terms by dividing both the numerator and denominator by 2.
Why divide by 2? 2 is the Greatest Common Divisor (GCD)
or Greatest Common Factor (GCF) of the numbers 16666 and 100000.
So, this fraction reduced to lowest terms is 8333/50000
So your final answer is: 0.16666 can be written as the fraction 8333/50000
Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!
