The answer is B. Light microscope
Answer:
% GENOTYPE
FF = 0%
Ff = 50%
ff = 50%
% PHENOTYPE
Black fur = 50%
Grey fur = 60%
Explanation:
This question involves a single gene coding for fur color in dogs. The allele for grey fur (F) is dominant over the allele for black fur (f). This means that a heterozygous dog (Ff) will have a grey fur.
In this question, a heterozygous female (Ff) is said to cross with a recessive male (ff) i.e. Ff × ff. The following gametes will be produced by each parent:
Ff - F and f
ff - f and f
Using these gametes in a punnet square (see attached image), the following genotypic proportion of offsprings will be produced:
Ff - 1/2 = 50%
ff - 1/2 = 50%
Ff is phenotypically GREY while ff is phenotypically BLACK. This means that 50% of the offsprings will be black and 50% will be grey.
There is a 3/4 chance their offspring will be black. If you make a Punnett's (I hope that's how you spell it) square then you will find that one offspring will be homozygous for black hair, two will be heterozygous with black hair, and one will be homozygous with brown hair. Therefore, there's a 3/4 chance the offspring will have black hair. Hope this helped!