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SVETLANKA909090 [29]
3 years ago
9

Using 50 boxes of nails a carpenter was able to finish 450 bird houses. Write an equation that can be used to express the relati

onship between the total number of birdhouses completed and the boxes of nails used.
Mathematics
1 answer:
arsen [322]3 years ago
8 0

Answer:

450 = 50x

Step-by-step explanation:

50x = 450

x = 450 / 50

x = 9

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Answer:

-1/2

Step-by-step explanation:

Rise/run=2/-4

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The amount of time that a 4th grader reads comic books in a week is normally distributed with a mean of 6 hours and a standard d
KATRIN_1 [288]

Answer:

0.9544 = 95.44% probability that the sample mean time for reading comic books per week is between 5 and 7 hours.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 6, \sigma = 2, n = 16, s = \frac{2}{\sqrt{16}} = 0.5

What is the probability that the sample mean time for reading comic books per week is between 5 and 7 hours

This is the pvalue of Z when X = 7 subtracted by the pvalue of Z when X = 5. So

X = 7

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{7 - 6}{0.5}

Z = 2

Z = 2 has a pvalue of 0.9772

X = 5

Z = \frac{X - \mu}{s}

Z = \frac{5 - 6}{0.5}

Z = -2

Z = -2 has a pvalue of 0.0228

0.9772 - 0.0228 = 0.9544

0.9544 = 95.44% probability that the sample mean time for reading comic books per week is between 5 and 7 hours.

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