Help on geometry. Please

Mathematics

1 answer:

Vika [28.1K]3 years ago

6 0

Answer:

AC<AB+BC

If you were to flatten out the distance AB and BC, logically speaking, you'd get a larger distance than the distance AC.

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Nancy is making a kite based on the pattern below. About how much binding does Nancy need to cover the edges of the kite?

Ainat [17]

Check the picture below.

so the perimeter of the kite is x+x+y+y, namely 2x + 2y.

$\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=\stackrel{hypotenuse}{x}\\ a=\stackrel{adjacent}{8}\\ b=\stackrel{opposite}{15}\\ \end{cases} \\\\\\ x=\sqrt{8^2+15^2}\implies x=\sqrt{289}\implies \boxed{x=17} \\\\[-0.35em] ~\dotfill$

$\bf \begin{cases} c=\stackrel{hypotenuse}{y}\\ a=\stackrel{adjacent}{8}\\ b=\stackrel{opposite}{4}\\ \end{cases}\implies y=\sqrt{8^2+4^2}\implies y=\sqrt{80}\implies \boxed{y\approx 8.94} \\\\[-0.35em] ~\dotfill\\\\ 2x+2y\implies 2(17)+2(8.94)\implies 51.88\implies \stackrel{\textit{rounded up more}}{51.9}$

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4 years ago

Write -4 3/8 as a decimal

Likurg_2 [28]

-4 x 8= -32+3=-29. -29/8= -3.625

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3 years ago

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Aleks [24]

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Step-by-step explanation:

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Find lim f(x), x->3-<br> Can you please explain this. I dont know why but this is confusing me.

GaryK [48]

Hello,

$$ \lim_{x \to 3-} f(x)=1\ \ is\ since ( x\ \in\ Dom(f)\ and\ \forall\ \delta\ \textgreater\ 0 \ and\ $
$
$( x \in \ Dom( f ) \ and \ 3-\delta \ \le \ x \ \ \textless \ p ) == \textgreater \ 
1 - \epsilon \ \le\ f ( x )\ \le \ 1 + \epsilon \$

$$ \lim_{x \to 3+} f(x)=3$
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3 years ago

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kati45 [8]

Answer is 30

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EACH= MULTIPLY

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3 years ago

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