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Sedbober [7]
3 years ago
10

The distance in nautical miles that you can see with a periscope is 1.17 times the square root of h, where h is the height of th

e periscope above the water, measured in feet. Can you see twice as far with a periscope that is 6 feet above the water than with a periscope that is three feet above the water? Explain.
Mathematics
2 answers:
IceJOKER [234]3 years ago
6 0

Answer:

So with the periscope raised to 4 feet above the surface, the horizon is 2 nm ... As I recall the rough thumb rule was that distance to the horizon in nautical miles is the square root of height of eye ... feet can be seen from the surface of the water at 10 miles, or by a periscope ... The closer you get, the more of the ship you see.

Step-by-step explanation:

zhuklara [117]3 years ago
6 0
I seen you got the answer , so I’m just stopping by to say hi
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Suppose a household’s income increases from $2500 to $3000 and quantity demanded changes from 190 to 150. What is the income ela
shusha [124]

The income elasticity for the household is -1.05.

<h3>What is the income elasticity?</h3>

Income elasticity measures how quantity demanded changes when there is a change in the income of a person / household

Income elasticity = percentage change in quantity demanded / percentage change in income

  • percentage change in income = (3000 / 2500) - 1 = 0.2 = 20%
  • percentage change in quantity demanded =( 150 /190) - 1 = -0.21 = -21%

Income elasticity = -21% / 20 = -1.05

To learn more about income elasticity, please check: brainly.com/question/15313354

#SPJ1

6 0
2 years ago
Simplify: <br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B6%5E%7B3%7D-7%5Ccdot3%5E%7B4%7D-2%5E%7B5%7D%5Ccdot9%7D%7B%5Cleft%281-
klio [65]

Answer:

Simplifed:

\frac{6^{3}-7\cdot3^{4}-2^{5}\cdot9}{\left(1-2^{3}\right)^{3}+7^{3}}

\frac{6^{3}-7\cdot3^{4}-2^{5}\cdot9}{\left(1-2^{3}\right)^{3}+7^{3} } \\  \frac{216 - 567 -288 }{ { - 7}^{3} +  {7}^{3}  }  \\  \frac{ - 639}{0}

infinity

6 0
3 years ago
Please help me with this​
Licemer1 [7]

Answer:

`184.61

Step-by-step explanation:

i got this by dividing the 3000 by the price of 32.50 and then multiplying it by 2 to get the depth im not fully sure if this is correct but i tried and i hope this helps!

3 0
4 years ago
A particular type of cell increases by 75% in number every hour. Find the number of cells present at the end of 12 hours if ther
prisoha [69]

We have been given that a particular type of cell increases by 75% in number every hour. We are asked to find the number of cells present at the end of 12 hours if there are initially 4 of these cells.

We will use exponential growth formula to solve our given problem.

y=a\cdot (1+r)^x, where,

y = Final amount,

a = Initial amount,

r = Growth rate in decimal form,

x = Time.

75\%=\frac{75}{100}=0.75

Upon substituting initial value a=4 and x=12 in above formula, we will get:

y=4\cdot (1+0.75)^{12}

y=4\cdot (1.75)^{12}

y=4\cdot 825.0050068497657776

y=3300.020027

y\approx 3300

Therefore, there will be approximately 3300 cells at the end of 12 hours.

5 0
4 years ago
In a small Library there are five non-fiction books for every nine fiction book there are 130 Non-fiction books how many fiction
vova2212 [387]

Answer:

For 130 non-fiction books, the number of fiction books can be from 270 to 278.

Step-by-step explanation:

Given that, there are 5 non-fiction books for every 9 fiction books.

Observe that, if the number of fiction books is less than 9, than there will be no no-fiction books.

So, there are 5 non-fiction books for every 9 to (9+8) fiction books

So, by elementary method, there will be 5n non-fiction books for every 9n+8 fiction books, where n is a natural number.

Or, if the number of non-fiction books is 5n, then the number of fiction books will be ranging from 9n to (9n+8).

For, 150 non-fiction books, 5n=150 or n=150/5=30.

Hence, the number of fiction books can be from 9n to (9n+8).

=9x30 to (9x30+8)

=270 to 278.

Hence, for 130 non-fiction books, the number of fiction books can be from 270 to 278.

6 0
4 years ago
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