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Diano4ka-milaya [45]
2 years ago
6

What is the slope of the line given by the equation -3x = 30 - 5y?

Mathematics
1 answer:
zaharov [31]2 years ago
8 0

Answer:

The slope of the line given by the equation -3x=30-5y is \frac{3}{5}.

Step-by-step explanation:

-3x=30-5y

Move the -3x to the right side of the equal sign and the -5y to the left.

5y=30+3x

By switching them to opposite sides, their sign changes from - to +.

Then, divide both sides by 5 in order to isolate the y.

\frac{5y}{5} = \frac{30+3x}{5}

You get:

<em>y= </em>\frac{3}{5} x +6<em />

According to y=mx+b, mx refers to the slope.

In this case, the slope would be \frac{3}{5}.

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Answer:

12 cm

Step-by-step explanation:

The formula for the area of a trapezoid is written as:

1/2(b1 + b2)h

h = height = 16 cm

b1 = Length of one parallel side = 9cm

b2 = Length of second parallel side = ?

Area of trapezoid = 168cm²

The formula to find the length of the second parallel side =

b2 = 2A/h - b1

b2 = 2 × 168/16 - 9

b2 = 336/16 - 9

b2 = 21 - 9

b2 = 12cm

Therefore, the length of the second parallel side is 12 cm

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2 years ago
Use your calculator to select the best answer below:
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Answer:

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Step-by-step explanation:

\lim_{x \to a} \frac{a-x}{\sqrt{x} -\sqrt{a} } \\ =-\lim_{x \to a} \frac{x-a}{\sqrt{x} -\sqrt{a} }  \\=-\lim_{x \to a} \frac{(\sqrt{x} -\sqrt{a})(\sqrt{x} +\sqrt{a})}{\sqrt{x} -\sqrt{a} }  \\=- \lim_{x \to a} \sqrt{x} +\sqrt{a}\\=-2\sqrt{a}

6 0
2 years ago
BRAINLIEST PLS HELP <br><br> Solve for x:<br><br><br><br> x = 10<br> x = 30<br> x = 0<br> x = 1
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Answer:

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Step-by-step explanation:

4 0
3 years ago
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Answer:

6 years

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Simple interest= P.R.T

I = $1300

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