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Can someone give me the answers plz:)

Alborosie

Remark

There is no short way to do this problem and no obvious way to get the answer other that to solve each part.

Solve

A

$\dfrac{x + 1.6}{2} =\text{x + 0.1}$ Multiply by 2

x + 1.6 = 2(x + 0.1) Remove the brackets

x + 1.6 = 2x + 0.1*2

x + 1.6 = 2x + 0.2 Subtract x from both sides

1.6 = x + 0.2 Subtract 0.2 from both sides

1.6 - 0.2 = x

1.4 = x

Circle A

B

Subtract 2x from both sides.

3x - 2x = 1.4

Circle B

C

Remove the brackets.

4x + 6 = 2x - 6 Add 6 to both sides

4x + 12 = 2x Subtract 4x from both sides.

12 = -2x Divide by - 2

12/-2 = x

x = - 6 Don't circle C

D

I'm going to be very scant in my solution of this. You can fill in the steps.

3x = 4.2

x = 4.2/3

x = 1.4

Circle D

5 0

3 years ago

Read 2 more answers

Which expression is equivalent to (2^1/2 2^3/4)^2

dimaraw [331]

Answer:

$\sqrt{2^5}$

Step-by-step explanation:

$2^{1/2}$ × $2^{3/4}$ = $2^{5/4}$

( $2^{5/4}$ )² = $2^{5/2}$ = $\sqrt{2^5}$

6 0

3 years ago

Read 2 more answers

An asset is something...

IceJOKER [234]

Answer:

The Answer is Something owned.

Step-by-step explanation:

please give brainliest.

5 0

3 years ago

A taste test asks people from Texas and California which pasta they prefer, brand A or brand B. The table shows the results. A p

Maurinko [17]

Answer:

A

Step-by-step explanation:

It would be A because there are 45 people in Texas that prefer brand B. There are 105 people in total that prefer brand B. 45/105 is .42857... so rounded it would be .43, therefore A. I hope this helps.

6 0

4 years ago

5. A scientist believes the concentration of radon gas in the air is greater that the established safe level of 4pci or less. Th

zysi [14]

Complete Question

A scientist believes the concentration of radon gas in the air is greater that the established safe level of 4 pci or less. The scientist tests the composition for 36 days finding an average concentration of 4.4 pci with a sample standard deviation of 1 pci.

a) In testing the scientist's belief, write the appropriate hypotheses:

$H_o:$ Ha:

b) What decision should be made?

Answer:

a

The null hypothesis is $H_o : \mu \le 4 \ pci$

The alternative hypothesis is $H_a : \mu > 4 \ pci$

b

There is sufficient evidence to conclude that the concentration of radon gas in the air is greater that the established safe level of 4pci or less

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 4 \ pci$

The sample size $n = 36 \ days$

The sample mean is $\= x = 4.4 \ pci$

The standard deviation is $\sigma = 1 \ pci$

The level of significance is $\alpha = 0.05$

The null hypothesis is $H_o : \mu = 4 \ pci$

The alternative hypothesis is $H_a : \mu > 4 \ pci$

Generally the test statistics is mathematically represented as

$t = \frac{ \= x - \mu }{ \frac{ \sigma}{ \sqrt{n} } }$

=> $t = \frac{ 4.4 - 4 }{ \frac{ 1}{ \sqrt{36} } }$

=> $t =2.4$

The p-value is mathematically represented as

$p-value = P(Z > 2.4 )$

From the z-table

$P(Z > 2.4 ) = 0.008$

$p-value =0.008$

So from this obtained value we see that

$p-value < \alpha$ so we reject the null hypothesis

Hence we can conclude that there is sufficient evidence to conclude that the concentration of radon gas in the air is greater that the established safe level of 4pci or less

4 0

3 years ago