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drek231 [11]
3 years ago
8

Pleaseeee help ASAP it’s due today :(

Mathematics
1 answer:
Aleksandr [31]3 years ago
5 0

Let, price increased by x times.

New price = 40 + ( 1 × x ) = 40 + x

It is given that for each $1 increase park loses 300 visitors.

Number of visitors = ( 24000 - 300x )

So, revenue is given by :

R = ( 24000 - 300x )( 40 + x )    ....1)

To finding critical point :

R'(x) = 0

-300( 40 + x )  + ( 24000 - 300x ) = 0     .....By product law

-12000 - 300x + 24000 -300x = 0

600x = 12000

x = 20

So, revenue is maximum at x = 20 .

Putting x = 20 in equation 1) , we get :

R = ( 24000 - 300x )( 40 + x )

R = [ 24000 - 300(20)][40 + 20 ]

R = $1080000

Therefore, park should charge $( 40 + 20 ) = $60 for maximising the revenue and maximum revenue is  $10,80,000  .

Hence, this is the required solution.

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14.44 (Letter D)

Step-by-step explanation:

The answer is 14.44

Hopefully its correct!!!

8 0
2 years ago
What are the solutions of the equation (2x + 3)^2 + 8(2x + 3) + 11 = 0? Use u substitution and the quadratic formula to solve.
iris [78.8K]
U=2x+3, x=u/2-3/2
u^2+8u+11=0
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x1=u1/2-3/2=-7/2+sqrt(5)/2
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7 0
3 years ago
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What is the rate of 13 inches of snow in 8 hours?
seraphim [82]

Answer: 1.625 inches of snow per hour

Step-by-step explanation:

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6 0
2 years ago
The length of a rectangle is eight more than twice its width. The perimeter is 96 feet. Find the dimensions of the rectangle
Debora [2.8K]

Answer:

The width  of the rectangle is 14'8",  and the length is 33'4"

Step-by-step explanation:

We're given two pieces of information:

The length is eight more than twice the width:

l = 2w + 4

The perimeter is 96 feet:

p = 96

We also need to apply one more piece of information that is not provided here, and that is the relationship between the perimeter of a rectangle, and it's length and width:

p = 2l + 2w

We can solve for w by plugging the other two values into the last:

p = 2w + 2l\\96 = 2w + 2(2w + 4)\\96 = 2w + 4w + 8\\88 = 6w\\3w = 44\\w = \frac{44}{3}\\w = 14\frac{2}{3}

Now we can find the length by plugging w into the first equation:

l = 2w + 4\\l = 2(14\frac{2}{3}) + 4\\l = 29\frac{1}{3} + 4\\l = 33\frac{1}{3}

One third of  a foot is four inches, so the width is 14'8" and the length is 33'4"

To make sure our answer is correct, we should plug those numbers back into the area equation and see if we're right:

p = 2l + 2w\\p = 2(33\frac{1}{3}) + 2(14\frac{2}{3})\\p = 66\frac{2}{3} + 29\frac{1}{3}\\p = 96

So we know our answer's correct

8 0
2 years ago
Solve the equation?
stiks02 [169]

Answer:

A

Step-by-step explanation:

Given

p² + 2p - 8 = 0 ← in standard form

with a = 1, b = 2, c = - 8

Using the quadratic formula to solve for p

p = ( - 2 ± \sqrt{2^2-(4(1)(-8))} / 2

  = ( - 2 ± \sqrt{4+32} / 2

  = ( - 2 ± \sqrt{36} ) / 2

p = \frac{-2-6}{2} = \frac{-8}{2} = - 4

p = \frac{-2+6}{2} = \frac{4}{2} = 2

5 0
3 years ago
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