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Anit [1.1K]
3 years ago
11

1) Solve for Side A. 2) Solve for Angle B.

Mathematics
2 answers:
damaskus [11]3 years ago
8 0

___________________________________

<h2>To find \tt{\overline{A}}</h2>

<h3>Given that: </h3>

\quad\quad\quad\quad\tt{ \angle{A = 115° }}

<h3>Using cosine rule:</h3>

\tt{\overline{A}²=b²+c²-2bc  \cos( \angle{a}) }

\tt{\overline{A}²=(30)²+(20)²-2(30)(20) \cos( \angle{115°}) }

\tt{\overline{A}²=900+400-2(600) \cos( \angle{115°}) }

\tt{\overline{A}²=1300-1200 \cos( \angle{115°}) }

\tt{\overline{A}   ²=1807.1419}

\tt{\overline{A}= \sqrt{ 1807.1419}}

\pink {\boxed{ \tt{ \overline{A}=42.51}}}

<h2>Now, to find \tt{ \angle{B}}</h2>

\tt{ cos\;B  =  \frac{ {a}^{2}  +  {c}^{2}   -   {b}^{2} }{2ac} }

\tt{ cos\:B  =  \frac{ {42.51}^{2}  +  {20}^{2}   -   {30}^{2} }{2(42.51)(20)} }

\tt{ cos\:B  =  0.7687}

\tt{ \angle{B}  =  { \cos}^{ - 1}  (0.7687)}

\pink{\boxed{\tt{ \angle{B}  =  {39.46°}}}}

___________________________________

#CarryOnLearning

✍︎ C.Rose❀

avanturin [10]3 years ago
4 0

Answer:

solution given;

let

AB=a

AC=b=30ft

AB=c=20ft

<A=115°

By using Cosine rule.

a²=b²+c²-2bc cos angle

a²=30²+20²-2*30*20 Cos 115°

a²=1807.1419

a=√[1807.1419]

a=42.51

Side A is 42.51ft.

Again

Cos B=\frac{a²+c²-b²}{2ac}

Cos B=\frac{42.51²+20²-30²}{2*42.51*20}

Cos B=0.7687

<B=Cos -¹(0.7687)

<B=39.46°

Angle B is 39.46

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