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horrorfan [7]
3 years ago
14

Please huryy!!

Mathematics
2 answers:
ArbitrLikvidat [17]3 years ago
8 0

Answer:

1.5

Step-by-step explanation:

yulyashka [42]3 years ago
4 0
Answer is 1.5 I think ...
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at which values of x does the graph of f(x)=x^2-x-2/(x^2-1)(x^2-16) have a vertical asymptope? check all that apply
katen-ka-za [31]

Answer:

x = -4, 1, 4

Step-by-step explanation:

The function is given as:

f(x) = (x² - x -2)/[(x² - 1)(x² -16)]

We want to find the values of x where the graph will have vertical assymptote.

Vertical asymptotes are defined as vertical lines which correspond to the values of x that will make the denominator of a rational function to be zero.

Thus, to get the values of x that we will have vertical assymptotes, we have to equate the denominator to zero.

We have;

[(x² - 1)(x² -16)] = 0

Thus,

x² - 1 = 0

Or

x² - 16 = 0

So;

x² = 1

x = √1

x = 1

Or

x² = 16

x = ±√16

x = ±4

Values of x that give vertical assymptote are;

x = -4, 1, 4

3 0
3 years ago
ANSWER FOR BRAINIEST
Rina8888 [55]
THE ANSWER IS: y=3/2x+1

to find a line that is perpendicular, invert the slope and multiply by -1
so the original slope is -2/3,
invert it to get -3/2 then multiply by -1 to get 3/2

put the given point (-2,-2) and the new slope into point intercept form: y+2=3/2(x+2)

rewrite in standard form to get y=3/2x+1
5 0
3 years ago
Please answer... Question is in the picture.
lawyer [7]
Answer: your answer is c

8 0
3 years ago
Read 2 more answers
So so sorry, but i have another one~ in this, the numbers can be used only once
Aliun [14]

Answer:

1 + 2 + 3 + 4 + 5 + 9=24

10 + 9 + 8 + 2 + 1 + 6=36

Step-by-step explanation:

When you mean you can only use the numbers once do you mean you can't use it twice on the same one or you can't use the number after you have used it on one of them?  

6 0
3 years ago
Read 2 more answers
A cuboid, with dimensions 28cm by 16cm by 15cm, has a volume of 6720cm cube. The cuboid is melted to form smaller cubes of lengt
Dovator [93]

Answer:

Vol of the cube =Vol of cubiod

Vol of each smaller cube =s×s×s= 4×4×4=64

Vol of cuboid /Vol of each smaller cube = no of cubes that can be obtained

6720/64= 105

Hence 105 cubes can be obtained

3 0
4 years ago
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