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aleksandr82 [10.1K]
2 years ago
6

PLEASE HELP!! WILL GIVE BRAINLIEST

Mathematics
1 answer:
Anna71 [15]2 years ago
7 0

Answer:

If your asking which answer the thing is, its 2.

Step-by-step explanation:

Can't explain, I hope you understand . . .

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Step-by-step explanation:

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How much do i need to get to 500 so rite now I have 423 and I need 500
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Step-by-step explanation:

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3 years ago
A survey of 865 voters in one state reveals that 408 favor approval of an issue before the legislature. Construct the 95% confid
katrin [286]

Answer:

The 95% confidence interval for the true proportion of all voters in the state who favor approval is (0.4384, 0.5050).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 865, \pi = \frac{408}{865} = 0.4717

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4717 - 1.96\sqrt{\frac{0.4717*0.5283}{865}} = 0.4384

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4717 + 1.96\sqrt{\frac{0.4717*0.5283}{865}} = 0.5050

The 95% confidence interval for the true proportion of all voters in the state who favor approval is (0.4384, 0.5050).

6 0
3 years ago
Please help if you want brianleist (no links please!) Ty!
nikitadnepr [17]

Answer:

The answer is 40 can I please get brainleist

5 0
3 years ago
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