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Luba_88 [7]
3 years ago
12

A bag of M&M's has 6 red, 5 green, 4 blue, and 8 yellow M&M's. What is the probability of randomly picking: (give answer

as a reduced fraction) 1) a yellow? w 2) a blue or green? 3) an orange?​
Mathematics
2 answers:
Dahasolnce [82]3 years ago
6 0

Answer:

P( yellow) =  8/23

P( blue or green) =  9/23

P(orange) = 0

Step-by-step explanation:

6 red, 5 green, 4 blue, and 8 yellow M&M's = 23  total

P( yellow) = yellow / total = 8/23

P( blue or green) = (blue+green) / total = (5+4)/23 = 9/23

P(orange) = orange/ total = 0/23

kenny6666 [7]3 years ago
3 0

Answer:

there are 23 m&m's.

Step-by-step explanation:

Probability of getting red is 6/23

Probability of getting  green is 5/23

Probability of getting blue is  4/23

Probability of getting yellow is 8/23

Orange = red + yellow = 6+8/23

Probability of getting Orange = 14/23

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2. A. 1620°

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6 0
3 years ago
PLEASE HELP<br><br> Graph the ordered pairs for y = 3x + 3 using r = {-2, 1, 2}.
Fed [463]

9514 1404 393

Answer:

  (-2, -3), (1, 6), (2, 9) are plotted in the attached graph

Step-by-step explanation:

For x = -2, y = 3(-2) +3 = -3. The ordered pair is (-2, -3).

For x = 1, y = 3(1) +3 = 6. The ordered pair is (1, 6).

For x = 2, y = 3(2) +3 = 9. The ordered pair is (2, 9).

The graph is attached.

5 0
3 years ago
Read 2 more answers
Need help finding a constant k at which the function is continuous everywhere.
saveliy_v [14]

Answer:

k = -6/35

Step-by-step explanation:

To make the function continuous

kx^2 = x+k

These must be equal where the function is defined for two different intervals

This is at the point x=-6  so let x=-6

k(-6)^2 = -6+k

36k = -6+k

Subtract k from each side

36k-k = -6+k-k

35k = -6

Divide by 35

35k/35 = -6/35

k = -6/35


3 0
3 years ago
Read 2 more answers
A car dealership sells sedans and SUVs. In 2000, the ratio in which they were sold was 5:4. By 2010, the dealership had adjusted
babymother [125]
120 would be the correct answer on apex
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3 years ago
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Don't squeeze. Fiver shoppers buy Charmain toilet paper. One charmin out of 10 in this batch is defective-its unsqueezable. You
nikklg [1K]

Answer:

The probability of finding aleast one or more defective charmins = 0.40951

Step-by-step explanation:

The probability of not finding a defective charmin = 1

probability of finding defective charmain = 1-0.1 =0.9

The probability of not finding all five defective item =

Then,

probability of not finding all five defective item=0.59049

Thus,

The probability of finding atleast one or more defective chairmins = 1-0.59049

Therefore,

The probability of finding atleast one or more defective chairmins =0.40951

7 0
2 years ago
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