A bag of M&M's has 6 red, 5 green, 4 blue, and 8 yellow M&M's. What is the probability of randomly picking: (give answer
as a reduced fraction) 1) a yellow? w 2) a blue or green? 3) an orange?
2 answers:
Answer:
P( yellow) = 8/23
P( blue or green) = 9/23
P(orange) = 0
Step-by-step explanation:
6 red, 5 green, 4 blue, and 8 yellow M&M's = 23 total
P( yellow) = yellow / total = 8/23
P( blue or green) = (blue+green) / total = (5+4)/23 = 9/23
P(orange) = orange/ total = 0/23
Answer:
there are 23 m&m's.
Step-by-step explanation:
Probability of getting red is 6/23
Probability of getting green is 5/23
Probability of getting blue is 4/23
Probability of getting yellow is 8/23
Orange = red + yellow = 6+8/23
Probability of getting Orange = 14/23
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