Answer:
60 oz of water to add
45 oz of 35% salt solution should be used
Step-by-step explanation:
Let x = amt no. ounces in the first solution
and 105 - x = amt no. of ounces in the second solution
Ist solution contains 0% salt
2nd solution contains .35(105 - x) salt
.15(105= amt of salt in mix
So.
amt of salt in 1st solution + amt of salt in 2nd solution = amt of salt in the mix
0 + .35(105 - x) = .15(105)
Let's get rid of the fractions by multipying thru the equation by 100
35(105 - x) = 15(105)
3675 - 35x = 1575
-35x = -2100
x = 60 oz of water to add
105 - 60 = 45 oz of 35% salt solution should be used
85/5
(50+35)/5
50/5 + 35/5
10+7=17
Answer: 249800
Step-by-step explanation:
Uhh you round it.
Answer:
see I need help for chemistry pls anyone here helps me I must submit before 10:30
Answer:
Step-by-step explanation:
c - 0.06c = 0.94c
total bill = 0.94c
