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kifflom [539]
2 years ago
6

Simplify the radical 7√7-2√28

Mathematics
2 answers:
Umnica [9.8K]2 years ago
7 0

ANSWER

3 \sqrt{7}

EXPLANATION

The given radical is

7 \sqrt{7}  - 2 \sqrt{28}

Remove the perfect square from the second radical.

= 7 \sqrt{7}  - 2 \sqrt{4 \times 7}

= 7 \sqrt{7}  - 2 \sqrt{4}  \times  \sqrt{7}

= 7 \sqrt{7}  - 2  \times 2 \times  \sqrt{7}

= 7 \sqrt{7}  - 4 \sqrt{7}

Subtract the like radicals

= 3 \sqrt{7}

lions [1.4K]2 years ago
5 0

Answer:

7√7-2√28 = 3√7

Step-by-step explanation:

We have given the expression:

7√7-2√28

We have to simplify the expression.

As we know that:

√28 = √4×7

Then we have,

7√7-2√28 = 7√7-2√4×7

7√7-2√28 = 7√7-2√4×√7

7√7-2√28 = 7√7-2×2×√7

7√7-2√28 = 7√7-4√7

7√7-2√28 = 3√7

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