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PtichkaEL [24]
3 years ago
15

PLS HELP ASAP!! Choose the correct answer:

Mathematics
1 answer:
Gemiola [76]3 years ago
4 0
Im late do you still need the answer aa it wont send aaa
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What type of arc is AB
stiv31 [10]

I'm sorry I don't know the answer but I do have to say that you are loved and no matter how many mistakes you make you will still always be loved.                        Step-by-step explanation:

3 0
2 years ago
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What value of b makes the trinomial below a perfect square x^2-bx+100
Aloiza [94]
1. Perfect square trinomials, are 2nd degree polynomials, of the form          a x^{2} +bx+c so that a \neq 0, b \neq 0, c \neq 0, which can be written as perfect squares.

2. For example (x+1) ^{2} = x^{2} +2x+1
 
(3x-1)^{2}= (3x)^{2}-2(3x)+(-1) ^{2}= 9x^{2}-6x+1    


3. Thus x^{2} +2x+1, 9x^{2}-6x+1 are perfect square trinomials.

4. x^{2} -bx+100= x^{2} -bx+ 10^{2}= (x+10)^{2}   or  (x-10)^{2}

5. In the first case -b=20, so b=-20. In the second case, -b=-20, so b=20.

6. b∈{-20, 20}
6 0
3 years ago
PLEASE can anyone help me with this problem??
Lilit [14]

9514 1404 393

Answer:

  4

Step-by-step explanation:

To find the value of g(7), locate 7 on the x-axis. Follow the grid line upward until it meets the graph (blue line). At that point, follow the grid line to the left until it meets the y-axis. Read the value from the scale on the y-axis.

  g(7) = 4

5 0
3 years ago
Please someone help me and do not just write anything explain thank you . use the information provided to write the vertex form
notka56 [123]
Ok, so user says that it should be solve for vertex not vertex form
(x,y)
to find the vertex of
y=ax^2+bx+c

the x value of the vertex is -b/2a
the y value is found by plugging in the x value for the vertex back into the original equation and evaluating


y=-2x^2-12x-28
a=-2
b=-12

xvalue of vertex is -(-12)/(2*-2)=12/-4=-3

x value of vertex is -3

plug backin for x
y=-2x^2-12x-28
y=-2(-3)^2-12(-3)-28
y=-2(9)+36-28
y=-18+8
y=-10

yvalue is -10
x value is -3

vertex is (-3,-10)
5 0
3 years ago
What is an equation of the line that passes through the points (-6, 2)and (−6,6)?
monitta

Answer:

x=-6

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(6-2)/(-6-(-6))

m=4/(-6+6)

m=4/0

undefined

x=-6

4 0
2 years ago
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