HELP PLEASE BE QUICK WILL GIVE BRAINLIEST.

Jessie's bus ride to school is 5 minutes more then 2/3 the time roberts bus ride. if jessie's time riding the bus is y and rober

Rainbow [258]

X=2/3y because you want to know what roberts time is

7 0

3 years ago

I dont understand this.

creativ13 [48]

Answer: J

Step-by-step explanation:

4 0

3 years ago

if it takes 28 drops of green food coloring to turn a gallon of milk green. How many drops would it take to turn an 8 ounces cup

Ber [7]

Answer:

7/4 or 1.75 drops

Step-by-step explanation:

In one gallon there are 128 ounces, if it takes 28 drops of coloring to turn 128 ounces of milk green then:

28/128

7/32

it takes 7/32 drops of food coloring to turn one ounce of milk green.

for 8 ounces, you multiply it by 8:

8*7/32

7/4≈1.75

∴ It would take 1.75 or 7/4 drops of coloring to turn 8 ounces of milk green.

8 0

4 years ago

Suppose that 10% of the fields in a given agricultural area with about 2,500 fields are infested with the sweet potato white fly

aleksley [76]

Answer:

a. 250 fields

b. 220 to 280 fields

c. Fields are not independent

Step-by-step explanation:

a. The average number of fields sampled that are infested with whitefly =

number of fields X Percentage sampled, 10%

= 2500 X 10% = 250 fields

b. Going by the binomial distribution is the square of the standard deviation, divided by (the product of the sample size n, and the probability a and b). While the standard deviation is the square root of the variance

σ = √nab

= √na(1-a) = √2500 X 10% X (1- 10%)

= √225 = 15

Now let's use the empirical rule that says about 95% of the observations are within two standard deviations from the mean since the number of trials is very large

μ - 2σ = 250 - 2(15) = 220

μ + 2σ = 250 + 2(15) = 280

Approximately 220 to 280 fields are expected to be infested going by 95% probability observation

c. Since x=25 is considered small and is not captured within 220 and 280 fields making one of the characteristics of binomial experiment not satisfied which expects each field to be independent. Making fields that are close together more likely to be infected.

5 0

3 years ago

In a survey of 1,003 adults concerning complaints about restaurants, 732 complained about dirty or ill-equipped bathrooms and 38

Ganezh [65]

Answer:

a

$0.716 < p < 0.744$

b

$0.3498 < p < 0.4089$

c

With the result obtained from a and b the manager can be 95 % confidence that the proportion of the population that complained about dirty or ill-equipped bathrooms are within the interval obtained at a

and that

the proportion of the population that complained about loud or distracting diners at other tables are within the interval obtained at b

Step-by-step explanation:

From the question we are told that

The sample size is $n = 1003$