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3 years ago

Please find the value of x.

Mathematics

1 answer:

makkiz [27]3 years ago

8 0

Answer:

x = 47

Step-by-step explanation:

360 = 3x+17+2x-10+x+71

360= 6x+78

282= 6x

47 = x

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A table of values of a linear function is shown below.

ikadub [295]

Given:

A table of values of a linear function.

To find:

The slope, y-intercept and equation of the function.

Solution:

Take any two points on the table.

Let the points are (-1, -3) and (0, -6).

Slope of the line:

$$m=\frac{y_2-y_1}{x_2-x_1}$

$$m=\frac{-6-(-3)}{0-(-1)}$

$$m=\frac{-6+3}{0+1}$

$$m=\frac{-3}{1}$

m = -3

Slope of the function = -3

y-intercept of the function is the point where x = 0.

In the table y = -6 when x = 0

y-intercept = -6

Equation of a line:

y = mx + c

where m is the slope and c is the y-intercept

y = -3x + (-6)

y = -3x - 6

Equation of a function is y = -3x - 6.

3 0

3 years ago

Four times a number added to seven times the number equals 55

VLD [36.1K]

Its 12 because 4 times 12 is 48 if you add 7 to 48 you get 55

5 0

3 years ago

Read 2 more answers

What should be subtracted from -8xy + 2x^2 + 3y^2 to get x^2 + 2

Minchanka [31]

Answer:

x^2 - 8xy + 3y^2 - 2

Step-by-step explanation:

(-8xy + 2x^2 + 3y^2) - unknown = x^2 + 2

- unknown = x^2 + 2 + 8xy - 2x^2 - 3y^2

- unknown = -x^2 + 8xy - 3y^2 + 2

Unknown = x^2 - 8xy + 3y^2 - 2

Check:

(-8xy + 2x^2 + 3y^2) - (x^2 - 8xy + 3y^2 - 2)

= -8xy + 2x^2 + 3y^2 - x^2 + 8xy - 3y^2 + 2

= -8xy + 8xy + 2x^2 - x^2 + 3y^2 - 3y^2 + 2

= x^2 + 2

8 0

3 years ago

8x(5+7). please answer will give 10 pts & brainiest

Veseljchak [2.6K]

Answer:

Step-by-step explanation:

8x(5+7)

Parentheses first

8* (12)

Then multiply

8 0

3 years ago

Read 2 more answers

(3-4i)(6i+7)-(2-3i)

Sergeu [11.5K]

Answer:

43-7i

Step-by-step explanation:

We are given the expression:

$\displaystyle \large{(3 - 4i)(6i + 7) - (2 - 3i)}$

First, expand 3-4i in 6i+7. To expand binomial with binomial, first we expand 3 in 6i+7 then expand -4i in 6i+7.

$\displaystyle \large{[(3 \cdot 6i) + (3 \cdot 7) + ( - 4i \cdot 6i) + ( - 4i \cdot 7)]- (2 - 3i)} \\ \displaystyle \large{[18i + 21 - 24 {i}^{2} - 28i]- (2 - 3i)}$

Now combine like terms.

$\displaystyle \large{[ - 10i+ 21 - 24 {i}^{2} ]- (2 - 3i)}$

Imaginary Unit

$\displaystyle \large{i = \sqrt{ - 1} } \\ \displaystyle \large{ {i}^{2} = - 1 }$

Therefore:-

$\displaystyle \large{[ - 10i+ 21 - 24 ( - 1) ]- (2 - 3i)} \\ \displaystyle \large{[ - 10i+ 21 + 24]- (2 - 3i)} \\ \displaystyle \large{[ - 10i+ 45]- (2 - 3i)}$

Then expand negative sign in 2-3i; remember that negative times negative is positive and negative times positive is negative.

$\displaystyle \large{- 10i+ 45 - (2 - 3i)} \\ \displaystyle \large{- 10i+ 45 - 2 + 3i}$

Combine like terms.

$\displaystyle \large{43 - 7i}$

5 0

3 years ago