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Lemur [1.5K]
3 years ago
13

An _____has income and expenses

Mathematics
2 answers:
OlgaM077 [116]3 years ago
8 0

Answer:

An income statement

Step-by-step explanation:

diamong [38]3 years ago
6 0

Answer:

Step-by-step explanation:

1. An income statement has income and expenses. Income statement records all the finances of an individual or an organization for a certain period of time. 2. The three-legged stool represents retirement savings. Retirement savings is the process of putting aside some finances as savings for later part of life. 3. A 401-K is a type of retirement account. This is an account that is set up by the employer to put aside an amount from salary before the tax deductions. 4. The easily accessible part of an emergency fund is savings. This saving comes fetching at the time of the hour when there is need for it. 5. Working a second job helps meet savings goals can help you pay off debts quicker and fills in gaps in a budget. So we can simply say that having an extra income is always useful

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What is 700,000 + 9,000 + 60 + 7 in standard form?
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In a recent study, researchers found that 31 out of 150 boys aged 7-13 were overweight or obese. On the basis of this study can
AURORKA [14]

Answer:

1) Null hypothesis:p \leq 0.15  

Alternative hypothesis:p > 0.15  

2) The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) z_{crit}= 1.64

And the rejection zone would be z>1.64

4) Calculate the statistic  

z=\frac{0.207 -0.15}{\sqrt{\frac{0.15(1-0.15)}{150}}}=1.955  

5) Statistical decision  

For this case our calculated value is on the rejection zone, so we have enough evidence to reject the null hypothesis at 5% of significance and we can conclude that the true proportion is higher than 0.15

Step-by-step explanation:

Data given and notation

n=150 represent the random sample taken

X=21 represent the boys overweight

\hat p=\frac{31}{150}=0.207 estimated proportion of boy overweigth

p_o=0.15 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

1) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the true proportion of boys obese is higher than 0.15.:  

Null hypothesis:p \leq 0.15  

Alternative hypothesis:p > 0.15  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

2) The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Decision rule

For this case we need a value on the normal standard distribution who accumulates 0.05 of the area on the right tail and on this case this value is:

z_{crit}= 1.64

And the rejection zone would be z>1.64

4) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.207 -0.15}{\sqrt{\frac{0.15(1-0.15)}{150}}}=1.955  

5) Statistical decision  

For this case our calculated value is on the rejection zone, so we have enough evidence to reject the null hypothesis at 5% of significance and we can conclude that the true proportion is higher than 0.15

6 0
3 years ago
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